Study the following information carefully and answer the questions given below:

Six persons are arranged in descending order according to their weight from left to right. Only T is lighter than Q whose weight is 17kg. S is twice heavier than Q and 14 kg lighter than N. Two persons between M and S. R is not the second heaviest among all.

What may be the possible weight of R?

The correct answer is 39kg.

Let us analyze the given information step-by-step to determine the order and weights of the six persons from heaviest to lightest (descending order from left to right):

Let the six positions from left to right be:
1 (Heaviest) > 2 > 3 > 4 > 5 > 6 (Lightest)

Step 1: Determine the positions of Q and T
We are told that "Only T is lighter than Q". This means T must be the lightest person, occupying the 6th position, and Q must occupy the 5th position.
The weight of Q is given as 17 kg.
So, we have:
Position 5: Q (17 kg)
Position 6: T (< 17 kg)

Step 2: Determine the weights of S and N
S is twice as heavy as Q:
$\mathrm{Weight\; of\; S}=2\times 17=34kg$
S is 14 kg lighter than N, which means:
$\mathrm{Weight\; of\; N}=34+14=48kg$

Step 3: Analyze the positions of M and S
We are given that "Two persons are between M and S".
Since the weights of S (34 kg) and N (48 kg) are both greater than Q (17 kg), S and N must be placed in positions 1, 2, 3, or 4.
Let's look at the possible placements for S and M:
If S is at position 4, then M must be at position 1 (since there are two persons between them at positions 2 and 3).
If S is at position 1, then M must be at position 4. But if S is at position 1 (weight 34 kg), N (weight 48 kg) would have to be lighter than S to be placed to its right, which contradicts N > S. Thus, S cannot be at position 1.
Therefore, S must be at position 4 and M must be at position 1.

Step 4: Determine the positions of N and R
Now we have the following configuration:
Position 1: M
Position 2: (Empty)
Position 3: (Empty)
Position 4: S (34 kg)
Position 5: Q (17 kg)
Position 6: T
The remaining two persons are N (48 kg) and R.
Since N's weight is 48 kg, which is greater than S's weight (34 kg), N must occupy either position 2 or position 3.
We are given that "R is not the second heaviest among all." This means R cannot be at position 2.
Therefore, N must be at position 2 (second heaviest) and R must be at position 3 (third heaviest).
The final order of persons and their weights is:
M (> 48 kg) > N (48 kg) > R > S (34 kg) > Q (17 kg) > T (< 17 kg)

Step 5: Find the possible weight of R
From the final descending order, the weight of R must lie between the weight of N (48 kg) and the weight of S (34 kg):
$34kg<\mathrm{Weight\; of\; R}<48kg$
Looking at the given options:
- 18kg (Incorrect, since it is less than 34 kg)
- 39kg (Correct, since 34 kg < 39 kg < 48 kg)
- 30kg (Incorrect, since it is less than 34 kg)
- 22kg (Incorrect, since it is less than 34 kg)
- 53kg (Incorrect, since it is greater than 48 kg)

Thus, the only possible weight for R among the choices is 39kg.