Study the following information carefully and answer the questions given below-

Six persons are arranged in descending order according to their weight from left to right. Only T is lighter than Q whose weight is 17kg. S is twice heavier than Q and 14 kg lighter than N. Two persons between M and S. R is not the second heaviest among all.

What may be the possible weight of R?

Let us analyze the given information step-by-step to determine the order of the six persons by weight and find the possible weight of R.

We have 6 persons. Let's arrange them in descending order of weight from left to right (Position 1 is the heaviest, Position 6 is the lightest):
1 > 2 > 3 > 4 > 5 > 6

Step 1: Position of Q and T
The problem states: "Only T is lighter than Q".
This means that T must be the lightest person (Position 6), and Q is the second lightest person (Position 5).
So, the arrangement is:
_ > _ > _ > _ > Q > T
We are given that the weight of Q is 17 kg.

Step 2: Weight of S and N
"S is twice heavier than Q".
Weight of S = 2 * Weight of Q = 2 * 17 kg = 34 kg.
"S is 14 kg lighter than N".
Weight of N = Weight of S + 14 kg = 34 kg + 14 kg = 48 kg.

Step 3: Positioning S and M
Since the weights are in descending order:
Weight of N (48 kg) > Weight of S (34 kg) > Weight of Q (17 kg).
So N and S must be placed in positions 1 to 4.
The problem states: "Two persons between M and S."
Let's look at the remaining positions for S (Positions 1, 2, 3, 4):
- If S is at Position 4: The two persons between M and S would be at Positions 3 and 2, which means M must be at Position 1.
- If S is at Position 3: M would have to be at Position 6 (which is occupied by T) or we cannot place M. Thus, S cannot be at Position 3.
- If S is at Position 2: M would have to be at Position 5 (occupied by Q). So S cannot be at Position 2.
- If S is at Position 1: Two persons between M and S means M is at Position 4.

Let's test both valid cases:

Case A: S is at Position 4 and M is at Position 1
Arrangement: M > _ > _ > S > Q > T
Since Weight of N (48 kg) > Weight of S (34 kg), and M is heavier than S, N must be heavier than S. N can be at Position 2 or 3.
The remaining persons to place are N and R. This leaves positions 2 and 3 for them.
We are told: "R is not the second heaviest among all."
Position 2 is the second heaviest position. Therefore, R cannot be at Position 2. Thus, N must be at Position 2, and R must be at Position 3.
This gives the arrangement:
M > N > R > S > Q > T
Let's check the weights:
- Weight of N = 48 kg
- Weight of S = 34 kg
Since R is positioned between N and S, the weight of R must be between the weight of N and the weight of S:
34 kg < Weight of R < 48 kg

Case B: S is at Position 1 and M is at Position 4
Arrangement: S > _ > _ > M > Q > T
Since Weight of N (48 kg) > Weight of S (34 kg), N must be heavier than S. But here S is at Position 1 (the heaviest position), which would mean N cannot be placed because N must be heavier than S. Therefore, Case B is invalid.

Conclusion:
The weight of R must be between 34 kg and 48 kg.
Looking at the given options:
- 18 kg (not between 34 and 48)
- 39 kg (between 34 and 48)
- 30 kg (not between 34 and 48)
- 22 kg (not between 34 and 48)

Thus, the only possible weight for R among the options is 39 kg.