Study the following information carefully and answer the questions given below.
Seven boxes- A, B, C, D, E, F and G are kept one above another in a single stack but not necessarily in the same order.
Only two boxes are kept between box A and box F. Box B is kept two boxes above box F. Only three boxes are kept between box B and box G. The number of boxes kept above box G is one more than the number of boxes kept below box C. Box D is kept two boxes below box C. Box E does not kept below box D.

Which box is kept at the bottom-most position?

To determine the correct arrangement of the seven boxes (A, B, C, D, E, F, and G), we can construct the stack step-by-step by analyzing the given conditions.

Let us number the positions in the stack from 1 to 7, where 7 represents the top-most position and 1 represents the bottom-most position.

Step 1: Analyze the relationship between Box B, Box F, and Box A.
According to the clues:
- Box B is kept two boxes above box F. This means if F is at position $x$, then B is at position $x+2$.
- Only two boxes are kept between box A and box F.
This gives us two possible cases for the relative positions of A, B, and F:
Case 1: Box A is kept above Box F. In this case, A must be at position $x+3$. The order from top to bottom is: A, B, [empty], F.
Case 2: Box A is kept below Box F. In this case, A must be at position $x-3$. The order from top to bottom is: B, [empty], F, [empty], [empty], A.

Step 2: Use the clue about Box B and Box G.
We are told that only three boxes are kept between box B and box G.
- In Case 2, the span from A to B already covers 6 positions (from $x-3$ to $x+2$). Since there are only 7 boxes in total, let's test if we can place G:
If Box A is at position 1, then F is at 4, and B is at 6. The position of G, which has 3 boxes between it and B (at 6), must be:
$6-4=2$ (since G cannot be above B as that would exceed the 7-box limit).
So, G is at position 2. Let's write down this temporary arrangement:
Position 7: [Empty]
Position 6: B
Position 5: [Empty]
Position 4: F
Position 3: [Empty]
Position 2: G
Position 1: A

Step 3: Analyze the relationship between Box G and Box C.
We are given that the number of boxes kept above box G is one more than the number of boxes kept below box C.
With G at position 2, there are 5 boxes above G (positions 3, 4, 5, 6, and 7).
Let $N$ be the number of boxes below C. We have:
$5=N+1\Rightarrow N=4$
Since there must be 4 boxes below C, C must be at position 5. This fits perfectly since position 5 is currently vacant.

Step 4: Place the remaining boxes (D and E).
- We are told that box D is kept two boxes below box C. Since C is at position 5, D must be at:
$5-2=3$
This is also vacant, so we place D at position 3.
- The only remaining position is 7, which must be occupied by E.
- Finally, we check the condition: "Box E is not kept below box D." Since E is at position 7 and D is at position 3, E is above D, which satisfies this condition.

Final Stack Configuration (from top to bottom):
7. Box E
6. Box B
5. Box C
4. Box F
3. Box D
2. Box G
1. Box A

Comparing this with the bottom-most position (Position 1), we find that Box A is kept at the bottom-most position.