Study the following information carefully and answer the questions given below-

Six persons are arranged in descending order according to their weight from left to right. Only T is lighter than Q whose weight is 17kg. S is twice heavier than Q and 14 kg lighter than N. Two persons between M and S. R is not the second heaviest among all.

What may be the possible weight of R?

The correct answer is 39kg.

Let us analyze the given information step-by-step to determine the order and weights of the six persons from heaviest to lightest (descending order, left to right):
We have 6 positions: 1 (Heaviest) > 2 > 3 > 4 > 5 > 6 (Lightest).

Step 1: Determine the positions of Q and T
The problem states: "Only T is lighter than Q whose weight is 17kg."
This means T is the lightest person, and Q is the second lightest.
Therefore, Q is at position 5, and T is at position 6:
Position 5: Q = 17 kg
Position 6: T

Step 2: Determine the weights of S and N
"S is twice heavier than Q and 14 kg lighter than N."
From this, we can calculate S's weight:

$Weight\; of\; S\; =\; 2\; *\; 17\; kg\; =\; 34\; kg$

Now, we calculate N's weight since S is 14 kg lighter than N:

$Weight\; of\; N\; =\; Weight\; of\; S\; +\; 14\; kg\; =\; 34\; kg\; +\; 14\; kg\; =\; 48\; kg$

Step 3: Arrange M and S
"Two persons between M and S."
Since Q (17 kg) and T are at positions 5 and 6, and S (34 kg) is heavier than Q, S must occupy one of the positions from 1 to 4.
Let's consider the possible cases for placing S and M with two persons between them:
- Case A: S is at position 4. This means M must be at position 1 (leaving positions 2 and 3 in between).
- Case B: S is at position 1. This means M must be at position 4 (leaving positions 2 and 3 in between). However, if S is at position 1 (heaviest), then S's weight (34 kg) would be the maximum weight. But we know N's weight is 48 kg, which is greater than S's weight. Thus, N must be heavier than S, making Case B invalid.
Therefore, Case A is the only valid arrangement:
Position 1: M
Position 4: S (34 kg)

Step 4: Place the remaining persons (N and R)
The remaining positions to fill are 2 and 3. The remaining persons are N and R.
The problem states: "R is not the second heaviest among all."
Since position 2 is the second heaviest position, R cannot be placed there. Therefore:
Position 2: N (48 kg)
Position 3: R

The complete arrangement of the persons and their weights from heaviest to lightest is:
M > N (48 kg) > R > S (34 kg) > Q (17 kg) > T

Step 5: Determine the possible weight of R
From the established order, R's weight must lie strictly between the weight of N and the weight of S:

Let us evaluate the given options:
- 18kg (not in the range)
- 39kg (fits the range: 34 kg < 39 kg < 48 kg)
- 30kg (not in the range)
- 22kg (not in the range)
- 53kg (not in the range)

Thus, the only possible weight for R among the options is 39kg.