Study the following information carefully and answer the questions given below.
Seven persons – A, B, C, D, E, F and G go to watch a puppet show one after another but not necessarily in the same order.
D goes to the puppet show three persons before C. One person goes between C and G. As many persons go after G, as before F. F doesn’t go first to watch the puppet show. B goes immediately before A.

As many persons go before A as after___.

The correct option is E.

Step-by-step Explanation:

Let us arrange the seven persons (A, B, C, D, E, F, and G) in order from 1 (first person to go) to 7 (last person to go).

1. "D goes to the puppet show three persons before C."
This means there are two persons between D and C (Order: D _ _ C).

2. "One person goes between C and G."
So, G can be either 2 places before C or 2 places after C.

3. "As many persons go after G, as before F."
This means the position of F from the front is the same as the position of G from the back. Position(F) + Position(G) = 8.

4. "F doesn’t go first to watch the puppet show."
So, F cannot be at position 1. This also implies G cannot be at position 7.

5. "B goes immediately before A."
B and A form a block (B, A) together in consecutive positions.

Testing the possibilities:

Case 1: Let D be at position 1.
- Then C is at position 4 (since D is 3 persons before C).
- G can be at position 2 or position 6 (1 person between C and G).
- If G is at position 6: Then F must be at position 2 (since 1 person is after G, 1 person must be before F).
- Now available positions are 3, 5, 7.
- We need two consecutive spots for (B, A). The only consecutive spots remaining are not available, as position 3 is isolated (2-F, 4-C) and 5, 7 are separated by C. Thus, (B, A) cannot fit.
- If G is at position 2: Then F must be at position 6. Remaining positions for (B, A) would be 3, 5, 7, which again has no two consecutive vacant spots for B and A.

Case 2: Let D be at position 2.
- Then C is at position 5.
- G can be at position 3 or position 7.
- Since G cannot be at 7 (as F cannot be at 1), G must be at position 3.
- If G is at position 3 (4 persons after G), F must be at position 4 (3 persons before F, wait: 3rd from top means 2 before G, so F is 3rd from top: F=3, G=5 - let's check: Position of G is 3. Number of persons after G is 7 - 3 = 4. So number of persons before F must be 4, meaning F is at position 5. But C is already at 5, contradiction).

Case 3: Let D be at position 3.
- Then C is at position 6.
- G can be at position 4.
- Position of G = 4. Persons after G = 3. So persons before F = 3, which means F is at position 4. But G is at position 4, contradiction.

Case 4: Let D be at position 1, C at 4, G at 2:
Let's re-evaluate all combinations systematically:

Let the 7 positions be: 1, 2, 3, 4, 5, 6, 7.

Possible placements for D and C (D _ _ C):
- D=1, C=4
- D=2, C=5
- D=3, C=6
- D=4, C=7

Let's check D = 2, C = 5:
- G can be at 3 or 7.
- If G = 7, F must be at 1, but F cannot be at 1.
- If G = 3, persons after G = 4, so F = 5 (conflict with C = 5).

Let's check D = 3, C = 6:
- G can be at 4 (G=4 => F=4, conflict) or G can be at 8 (invalid).

Let's check D = 4, C = 7:
- G must be 1 person away from C, so G = 5.
- G = 5 => 2 persons after G => 2 persons before F => F = 3.
- Current placement: _ _ F D G _ C
- Positions filled: F at 3, D at 4, G at 5, C at 7.
- Remaining positions: 1, 2, 6.
- We need consecutive positions for B and A (B immediately before A).
- Positions 1 and 2 are vacant and consecutive! So B = 1, A = 2.
- The only remaining person is E, who goes to position 6.

Final Order:
1. B
2. A
3. F
4. D
5. G
6. E
7. C

Verification of conditions:
- D (4) goes 3 persons before C (7): Correct (4 is 3 before 7).
- One person (E at 6) between C (7) and G (5): Correct.
- Persons after G (5) = 2 (E, C). Persons before F (3) = 2 (B, A): Correct.
- F doesn't go first (F is 3rd): Correct.
- B goes immediately before A (B=1, A=2): Correct.

Question:
"As many persons go before A as after ___."
Number of persons before A (position 2) = 1 (only B).
We need to find the person who has exactly 1 person after them.
Person at position 6 (E) has exactly 1 person (C) after them.
Therefore, as many persons go before A as after E.