Study the given information carefully and answer the questions given below.
Nine people A, B, C, D, E, F, G, H, and I were born in different years i.e., 1998, 2000, 2003, 2004, 2005, 2010, 2012, 2015, and 2017 on the same date i.e., 31st December but not necessarily in the same order. Their ages are calculated as of 31st December 2021.
B is two years younger than A. The sum of the ages of C and D is 35, and C is older than D. The ages of F, G, and I are all perfect squares, where I is the youngest of the three and F is the oldest of the three. E is older than H.
How many persons were born between B and H?
Correct Answer :
More than four
Solution :
The correct option is More than four.
Step-by-Step Explanation:
Step 1: Calculate the age of each person as of 31st December 2021.
We subtract each birth year from the base year 2021:
• Born in 1998: years old
• Born in 2000: years old
• Born in 2003: years old
• Born in 2004: years old
• Born in 2005: years old
• Born in 2010: years old
• Born in 2012: years old
• Born in 2015: years old
• Born in 2017: years old
Step 2: Determine the positions of F, G, and I.
The clue states that the ages of F, G, and I are all perfect squares, where I is the youngest and F is the oldest.
Looking at the ages (23, 21, 18, 17, 16, 11, 9, 6, 4), the perfect squares are 16, 9, and 4.
Therefore:
• F = 16 years old (Born in 2005)
• G = 9 years old (Born in 2012)
• I = 4 years old (Born in 2017)
Step 3: Determine the positions of A and B.
The clue states that B is 2 years younger than A ().
Looking at the available ages not yet assigned (23, 21, 18, 17, 11, 6), the only two available ages with a difference of 2 are 23 and 21.
Therefore:
• A = 23 years old (Born in 1998)
• B = 21 years old (Born in 2000)
Step 4: Determine the positions of C and D.
The sum of the ages of C and D is 35, and C is older than D.
The remaining available ages are 18, 17, 11, and 6.
The pair that sums to 35 is 18 and 17 ().
Since C is older than D:
• C = 18 years old (Born in 2003)
• D = 17 years old (Born in 2004)
Step 5: Determine the positions of E and H.
The remaining ages are 11 and 6, and E is older than H.
Therefore:
• E = 11 years old (Born in 2010)
• H = 6 years old (Born in 2015)
Final Arrangement by Birth Year:
• 1998: A
• 2000: B
• 2003: C
• 2004: D
• 2005: F
• 2010: E
• 2012: G
• 2015: H
• 2017: I
Conclusion:
B was born in 2000 and H was born in 2015. The persons born between B and H are C, D, F, E, and G, which is a total of 5 persons.
Since 5 is more than four, the correct answer is More than four.
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