Question Details

The asymptotic Bode magnitude plot of a system is shown. Which one of the following options best represents the transfer function of the system?


Options

A

G(s) = 1 + s ω 0 s ω 0

B

G(s)=sω01+sω0


C

G(s)=1+sω01sω0


D

G(s)=1sω01+sω0

Show Answer

Correct Answer :

Option B

G(s)=sω01+sω0


Solution :

The correct answer is:
G ( s ) = s ω 0 1 + s ω 0

Analysis of the Bode Plot:
By inspecting the provided asymptotic Bode magnitude plot, we observe two main frequency regions separated by the corner frequency, which is labeled as ω0:
1. For high frequencies (ω>ω0), the magnitude plot is flat at a constant level of 0 dB.
2. For low frequencies (ω<ω0), the asymptote has a slope of -20 dB/decade when moving from low frequencies up towards ω0, representing a transition region where the magnitude changes with frequency.

Mathematical Derivation:
Let us evaluate the frequency response of the transfer function G(s) by substituting s=jω:
G ( j ω ) = j ω ω 0 1 + j ω ω 0

Now, we look at the asymptotic behavior in the two frequency limits:
Case 1: High-Frequency region (ωω0)
When the frequency is much higher than the corner frequency, the term jωω0 dominates over 1 in the denominator:
G ( j ω ) j ω ω 0 j ω ω 0 = 1
The magnitude in decibels in this region is:
| G ( j ω ) | dB = 20 log 10 ( 1 ) = 0 dB
This perfectly matches the flat asymptote of 0 dB for frequencies above ω0 shown in the plot.

Case 2: Low-Frequency region (ωω0)
When the frequency is much lower than the corner frequency, the term jωω0 is much smaller than 1, so the denominator is approximately 1:
G ( j ω ) j ω ω 0
The magnitude in decibels in this region is:
| G ( j ω ) | dB 20 log 10 ω ω 0
This mathematical form represents a straight line on a logarithmic scale with a slope of +20 dB/decade as frequency increases towards ω0. Correspondingly, as frequency decreases away from ω0, the magnitude rolls off at a rate of 20 dB/decade. Thus, the transfer function matching this behavior is indeed:
G ( s ) = s ω 0 1 + s ω 0

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