Question Details

The bar shows the total number of students in four schools and it also shows the difference between boys and girls in these schools.

In school E, the ratio of boys and girls be 7: 9 and boys in E is 50% more than girls in A and B together. Find the girls in E.

Options

A

48

B

54

C

36

D

32

Show Answer

Correct Answer :

Option B

54

54

Solution :

The correct answer is 54.

Step-by-step Explanation:

First, let us analyze the data given in the bar graph for each school:
- The blue bar represents the total number of students (Boys + Girls).
- The orange bar represents the difference between boys and girls (Boys - Girls). Assuming there are more boys than girls, we have:
For School A: Boys + Girls = 72, and Boys - Girls = 48.
For School B: Boys + Girls = 60, and Boys - Girls = 28.

Step 1: Calculate the number of girls in School A and School B

For School A:
Let the number of boys and girls in school A be represented by BoysA and GirlsA respectively.
We have two equations:
BoysA+GirlsA=72
BoysA-GirlsA=48
Subtracting the second equation from the first equation, we get:
2×GirlsA=72-48
2×GirlsA=24
GirlsA=12

For School B:
Let the number of boys and girls in school B be represented by BoysB and GirlsB respectively.
We have two equations:
BoysB+GirlsB=60
BoysB-GirlsB=28
Subtracting the second equation from the first equation, we get:
2×GirlsB=60-28
2×GirlsB=32
GirlsB=16

Step 2: Find the total number of girls in A and B together

Total girls in A and B = GirlsA + GirlsB
Total girls in A and B=12+16=28

Step 3: Find the number of boys in School E

We are given that the number of boys in E is 50% more than the girls in A and B together.
BoysE=28+(50% of 28)
BoysE=28+14=42

Step 4: Find the number of girls in School E

The ratio of boys to girls in School E is given as 7 : 9.
Let the number of boys in E be 7x and the number of girls in E be 9x.
Since the number of boys is 42, we set up the equation:
7x=42
x=6
Therefore, the number of girls in E is:
GirlsE=9x=9×6=54

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