Question Details

The cross-section of a steel T-beam is shown in the figure where all dimensions are in mm.

The plastic section modulus of the given cross-section is ______×104 mm3 (in integer).

Options

A

22

B

12

C

10

D

15

Show Answer

Correct Answer :

Option B

12

Solution :

The correct option is 12.

1. Analysis of Cross-Section Dimensions from the Image:
Based on the provided T-beam cross-section diagram:

  • The width of the top flange is 100 mm.
  • The thickness of the top flange is 20 mm.
  • The height (depth) of the vertical web is 100 mm.
  • The thickness (width) of the vertical web is 20 mm.

2. Calculation of Cross-Sectional Areas:
Let us calculate the area of the flange and the web separately:

A flange = 100 mm × 20 mm = 2000 mm 2

A web = 100 mm × 20 mm = 2000 mm 2

The total cross-sectional area is:

A total = A flange + A web = 2000 + 2000 = 4000 mm 2

3. Location of the Plastic Neutral Axis (PNA):
The plastic neutral axis (PNA) divides the total cross-section area into two equal halves. Since the tension and compression zones under fully plastic conditions must have equal areas:

A 1 = A 2 = A total 2 = 2000 mm 2

Because the flange area is exactly equal to 2000 mm2 and the web area is also 2000 mm2, the plastic neutral axis lies precisely at the junction of the flange and the web.

4. Centroidal Distances of the Halves from the PNA:
The area above the PNA (the flange) is a rectangle of depth 20 mm. Its centroid is located at a distance y1 from the PNA:

y 1 = 20 2 = 10 mm

The area below the PNA (the web) is a rectangle of depth 100 mm. Its centroid is located at a distance y2 from the PNA:

y 2 = 100 2 = 50 mm

5. Calculation of the Plastic Section Modulus (Zp):
The plastic section modulus is calculated as:

Z p = A 1 y 1 + A 2 y 2

Substituting the calculated values:

Z p = ( 2000 × 10 ) + ( 2000 × 50 )

Z p = 20000 + 100000 = 120000 mm 3

Expressing this value in the required units:

Z p = 12 × 10 4 mm 3

Therefore, the plastic section modulus factor is 12.

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