The data shows volume and height of 4 right circular tanks P, Q, R and S. The given data also depicts time taken to fill or empty the tank by inlet pipe A, B and outlet pipe C.

1. Ratio between time taken by pipe B and that by pipe C is different because pipes were used by the operator in different ways for different tanks.
2. Radius of tank S is 10.5 m.

Tank	Volume	Height	Time taken by pipe A to fill tank (in hours)	Ratio of time taken by pipe B to fill and pipe C to empty the tank
P	38808	28	10	2: 3
Q	--------	10	12	3: 2
R	5390	35	18	1: 3
S	19250	--------	---------	2: 5

Another tank Z has its height as 20% more than that of tank R and radius as 20% more than that of tank P. What is the sum of curved surface area of tank P and Z together (approximately)?

The correct option/answer is 10296 m³ (Note: The unit in the options is written as m³, which represents volume, but the question asks for the sum of the curved surface areas, which should conceptually be in square meters m². We will proceed to calculate the curved surface area in square meters to match the numeric value of the option).

Let's break down the solution step-by-step.

Step 1: Understand the dimensions of Tank P
Tank P is a right circular cylinder.
Given for Tank P:
Volume ($V$) = 38808 m³
Height ($h_P$) = 28 m

The volume of a cylinder is given by the formula:
$V=\pi r^{2}h$

Let $r_P$ be the radius of Tank P. Substituting the values:
$38808=\frac{22}{7}\times r_P^2\times 28$

Simplifying the equation:
$38808=22\times 4\times r_P^2$
$38808=88\times r_P^2$
$r_P^2=\frac{38808}{88}$
$r_P^2=441$
$r_P=\sqrt{441}=21\text{m}$

Step 2: Calculate the curved surface area (CSA) of Tank P
The curved surface area of a cylinder is given by:
${\text{CSA}}_P=2\pi r_P{h}_P$
${\text{CSA}}_P=2\times \frac{22}{7}\times 21\times 28$
${\text{CSA}}_P=2\times 22\times 3\times 28$
${\text{CSA}}_P=132\times 28=3696{\text{m}}^2$

Step 3: Determine the dimensions of Tank Z
Tank Z has:
- Height ($h_Z$) as 20% more than that of Tank R.
- Radius ($r_Z$) as 20% more than that of Tank P.

From the table, height of Tank R ($h_R$) = 35 m.
Thus, the height of Tank Z:
$h_Z=35\times 1.20=42\text{m}$

The radius of Tank Z:
$r_Z=21\times 1.20=25.2\text{m}$

Step 4: Calculate the curved surface area (CSA) of Tank Z
Using the curved surface area formula:
${\text{CSA}}_Z=2\pi r_Z{h}_Z$
${\text{CSA}}_Z=2\times \frac{22}{7}\times 25.2\times 42$
${\text{CSA}}_Z=2\times 22\times 25.2\times 6$
${\text{CSA}}_Z=44\times 151.2=6652.8{\text{m}}^2$

Step 5: Calculate the sum of the curved surface areas
Sum of curved surface areas of Tank P and Z:
$\text{Total CSA}={\text{CSA}}_P+{\text{CSA}}_Z$
$\text{Total CSA}=3696+6652.8=10348.8{\text{m}}^2$

Using $\pi \approx 3.14159$ or standard rounding approximations close to the given options, we find:
If we calculate with high precision:
${\text{CSA}}_P=2\times 3.14159\times 21\times 28\approx 3694.5$
${\text{CSA}}_Z=2\times 3.14159\times 25.2\times 42\approx 6650.1$
$\text{Total CSA}\approx 10344.6{\text{m}}^2$

Taking the closest option among the given values:
- 9375 m³
- 11548 m³
- 8935 m³
- 7365 m³
- 10296 m³

The closest value to 10348.8 m² is 10296 m³.