Question Details

The demand of a certain part is 1000 parts/year and its cost is ₹1000/part. The orders are placed based on the economic order quantity (EOQ). The cost of ordering is ₹100/order and the lead time for receiving the orders is 5 days. If the holding cost is ₹20/part/year, the inventory level for placing the orders is _________ parts (round off to the nearest integer).

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Correct Answer :

Correct answer is : 14

Demand, D = 1000 parts/year , Cost C = Rs. 1000/part

Co= Rs. 100/order, Ch = Rs. 20/part/year, Lead time LT = 5 days

EOQ =  2 D C o C h 2   × 1000 × 100 20 = 100

Number of orders = D/ EOQ = 1000 /100 = 10

Daily demand = 1000/ 365 = 2.73 ≈ 3

Reorder point = lead time × daily demand

Reorder point = 5 × 2.73 = 13.69 ≈ 14 parts

Solution :

The correct answer is 14.

Step-by-Step Explanation:

To determine the inventory level for placing the orders (also known as the Reorder Point), we need to find the demand during the lead time.

Let's first list the given parameters:
Annual demand, D = 1000 parts/year
Cost of the part, C = ₹1000/part
Cost of ordering, Co = ₹100/order
Holding cost, Ch = ₹20/part/year
Lead time, LT = 5 days

First, we calculate the Economic Order Quantity (EOQ) to understand the ordering parameters, although the reorder point primarily depends on the daily demand and the lead time:
EOQ = 2 × D × C o C h
Substituting the given values:
EOQ = 2 × 1000 × 100 20 = 100

Next, we calculate the daily demand. Since the annual demand is given per year, we convert it to a daily rate assuming 365 days in a year:
Daily demand = 1000 365 2.7397 parts/day

The reorder point (inventory level to place a new order) is the quantity of inventory that will be consumed during the lead time. It is calculated as:
Reorder point = Lead time × Daily demand
Substituting the lead time of 5 days and the daily demand:
Reorder point = 5 × 2.7397 = 13.698 parts

Rounding off to the nearest integer, we get:
Reorder point 14 parts

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