The following were prepared by dissolving 10g of glucose (C6H12O6) in 250 ml of water (P1), 10g of sucrose (C12H22O11) in 250ml of water (P3). The right option for the decreasing order of osmotic pressure of these solutions is :
Correct Answer :
P₂ > P₁ > P₃
Solution :
The correct option is P₂ > P₁ > P₃.
Note: In standard versions of this question, three solutions are compared: 10 g of glucose in 250 mL of water (P1), 10 g of urea in 250 mL of water (P2), and 10 g of sucrose in 250 mL of water (P3). We will include the calculations for all three to provide a complete explanation.
1. Understanding Osmotic Pressure:
Osmotic pressure () is a colligative property, which means it depends on the number of solute particles in the solution. The formula for osmotic pressure is given by:
Since the mass of each solute (10 g) and the volume of water (250 mL) are identical for all solutions, the concentration (and thus the osmotic pressure ) is inversely proportional to the molar mass () of the solute:
2. Molar Masses of the Solutes:
Let us calculate the molar mass for each solute:
• Glucose (C6H12O6):
• Urea (CH4N2O):
• Sucrose (C12H22O11):
3. Determining the Order of Osmotic Pressure:
Comparing the molar masses:
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