The major products obtained from the reactions in List-II are the reactants for the named reactions mentioned in List-I. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.

List-I	List-II
(P) Stephen reaction	(1) (i) CrO₂Cl₂ / CS₂     (ii) H₃O⁺     Toluene →
(Q) Sandmeyer reaction	(2) (i) PCl₅     (ii) NH₃     (iii) P₄O₁₀, Δ     Benzoic acid →
(R) Hoffmann bromamide degradation reaction	(3) (i) Fe, HCl     (ii) HCl, NaNO₂ (273–278 K), H₂O     Nitrobenzene →
(S) Cannizzaro reaction	(4) (i) Cl₂ / hν, H₂O     (ii) Tollens’ reagent     (iii) SOCl₂     (iv) NH₃     Toluene →
	(5) (i) (CH₃CO)₂O, Pyridine     (ii) HNO₃, H₂SO₄, 288 K     (iii) aq. NaOH     Aniline →

The correct option is: P → 2; Q → 3; R → 4; S → 1

Let us determine the major product for each reaction sequence in List-II and identify which named reaction in List-I uses that product as a reactant:

1. Analysis of reaction sequence (1):
Reactant: Toluene (C₆H₅-CH₃)
Reagents: (i) CrO₂Cl₂ / CS₂, followed by (ii) H₃O⁺.
This sequence represents the Etard reaction. Toluene is oxidized to Benzaldehyde (C₆H₅-CHO).
Benzaldehyde undergoes the Cannizzaro reaction (S) because it is an aldehyde that lacks α-hydrogen atoms. Therefore, S → 1.

2. Analysis of reaction sequence (2):
Reactant: Benzoic acid (C₆H₅-COOH)
Reagents:
(i) PCl₅ converts Benzoic acid to Benzoyl chloride (C₆H₅-COCl).
(ii) NH₃ converts Benzoyl chloride to Benzamide (C₆H₅-CONH₂).
(iii) P₄O₁₀, Δ is a strong dehydrating agent that dehydrates Benzamide to Benzonitrile (C₆H₅-CN).
Nitriles are the starting materials for the Stephen reaction (P) (reduction using SnCl₂ / HCl followed by hydrolysis to form aldehydes). Therefore, P → 2.

3. Analysis of reaction sequence (3):
Reactant: Nitrobenzene (C₆H₅-NO₂)
Reagents:
(i) Fe, HCl reduces Nitrobenzene to Aniline (C₆H₅-NH₂).
(ii) HCl, NaNO₂ (273–278 K) converts Aniline to Benzenediazonium chloride (C₆H₅-N₂⁺Cl^-).
Benzenediazonium chloride is the reactant for the Sandmeyer reaction (Q) (which yields chlorobenzene, bromobenzene, or benzonitrile upon reaction with copper(I) halides or copper(I) cyanide). Therefore, Q → 3.

4. Analysis of reaction sequence (4):
Reactant: Toluene (C₆H₅-CH₃)
Reagents:
(i) Cl₂ / hν converts Toluene to Benzyl chloride (C₆H₅-CH₂Cl) and subsequent hydrolysis (H₂O) yields Benzyl alcohol (C₆H₅-CH₂OH).
(ii) Tollens' reagent oxidizes Benzyl alcohol to Benzoic acid (C₆H₅-COOH).
(iii) SOCl₂ converts Benzoic acid to Benzoyl chloride (C₆H₅-COCl).
(iv) NH₃ converts Benzoyl chloride to Benzamide (C₆H₅-CONH₂).
Amides undergo the Hoffmann bromamide degradation reaction (R) when treated with Br₂ and a base to yield primary amines. Therefore, R → 4.

Conclusion:
Matching the entries:
P → 2
Q → 3
R → 4
S → 1