Question Details

The present age of a father is 4 years more than double the age of his son. After 10 years, the father's age is 30 years more than his son. Then the present age of father is:

Options

A

26 years

B

28 years

C

56 years

D

60 years

Show Answer

Correct Answer :

Option C

56 years

Solution :

The correct option is 56 years.

Let us break down the problem step-by-step to find the present age of the father.

Step 1: Define the variables for their present ages.
Let the present age of the son be represented by S years.
Let the present age of the father be represented by F years.

Step 2: Translate the first condition into an equation.
The problem states: "The present age of a father is 4 years more than double the age of his son."
Mathematically, this can be written as:

F = 2 S + 4

Let this be Equation (1).

Step 3: Translate the second condition into an equation.
The problem states: "After 10 years, the father's age is 30 years more than his son."
After 10 years:
The father's age will be F+10 years.
The son's age will be S+10 years.
According to the condition:

F + 10 = ( S + 10 ) + 30

We can simplify this equation by subtracting 10 from both sides:

F = S + 30

Let this be Equation (2). (Note: This indicates that the age difference between the father and the son is always 30 years.)

Step 4: Solve the equations to find the son's present age.
Since both equations express F in terms of S, we can set them equal to each other:

2 S + 4 = S + 30

Subtract S from both sides:

S + 4 = 30

Subtract 4 from both sides:

S = 26

So, the present age of the son is 26 years.

Step 5: Calculate the present age of the father.
Substitute the value of S=26 into Equation (2):

F = 26 + 30

F = 56

Thus, the present age of the father is 56 years.

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