The rotor of an aeroplane engine has mass moment of inertia 1.0 kg-m2. The engine rotates at speed of 500 RPM in clockwise direction if viewed from front of aeroplane. If aeroplane flying at 1200 km/hr turns with a radius of 2 km at same elevation. Then magnitude of gyroscopic moment by rotor on aeroplane structure is
Correct Answer :
8.73 N-m
Solution :
The correct option is 8.73 N-m.
To find the magnitude of the gyroscopic couple (or gyroscopic moment) exerted by the rotor on the aeroplane structure, we use the standard formula for the gyroscopic couple:
where:
• is the mass moment of inertia of the rotor.
• is the angular velocity of the rotor.
• is the angular velocity of precession (associated with the turning of the aeroplane).
Let's calculate each of these values step-by-step from the given data:
1. Mass moment of inertia ():
Given directly as:
2. Angular velocity of the rotor ():
The rotational speed of the engine is given as .
The relation between angular velocity and RPM is:
Substituting :
3. Angular velocity of precession ():
The linear speed of the aeroplane is . First, convert this speed into meters per second ():
The turn radius is given as .
The angular velocity of precession is:
4. Magnitude of the gyroscopic couple ():
Now substitute these values into the couple formula:
Using :
Thus, the magnitude of the gyroscopic moment acting on the aeroplane structure is indeed 8.73 N-m.
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