Read the information and answer the following questions.

The table shows the number of males working in private and public companies and number of females working in private and public company in four (A, B, C & D) different cities.

Cities	Males in Private company	Males in Public company	Females (private + public)
A	15x – 2y	y	55
B	16x	16	108
C	9y	24	74
D	84	21	85

Note – (i) Number of male employees in A are 50.

(ii) Total males working in private company from B and C are 154.
(iii) Total employees (male + female) working in any city = private companies + public company
(iv) Males/females working in any city = Sum of males/females working in private and public company

Males working in city C is approximately what percentage of females working from B?

The correct option is 106%.

Step 1: Understand the given table and notes

The table provides data for four different cities (A, B, C, and D) as follows:

• City A: Males in Private = 15x – 2y, Males in Public = y, Females (Private + Public) = 55
• City B: Males in Private = 16x, Males in Public = 16, Females (Private + Public) = 108
• City C: Males in Private = 9y, Males in Public = 24, Females (Private + Public) = 74
• City D: Males in Private = 84, Males in Public = 21, Females (Private + Public) = 85

Step 2: Find the values of x and y using the given conditions

From Note (i): Total males in City A = 50.
Total males in City A = (Males in Private company) + (Males in Public company)

$(15x-2y)+y=50$

$15x-y=50$   --- (Equation 1)

From Note (ii): Total males working in private companies from B and C = 154.
Males in Private company from B = 16x
Males in Private company from C = 9y

$16x+9y=154$   --- (Equation 2)

Step 3: Solve Equation 1 and Equation 2

Multiply Equation 1 by 9:

$9\times (15x-y)=9\times 50$

$135x-9y=450$   --- (Equation 3)

Add Equation 2 and Equation 3 together:

$(16x+9y)+(135x-9y)=154+450$

$151x=604$

$x=\frac{604}{151}=4$

Substitute x = 4 in Equation 1 to find y:

$15\left(4\right)-y=50$

$60-y=50$

$y=10$

Step 4: Calculate the required values

1. Males working in City C:
Males in Private (C) = 9y = 9 × 10 = 90
Males in Public (C) = 24
Total males working in City C = 90 + 24 = 114

2. Females working in City B:
Total females working from City B = 108

Step 5: Calculate the percentage

Percentage = (Total males in C / Total females in B) × 100

$\text{Percentage}=\frac{114}{108}\times 100$

$\text{Percentage}=\mathrm{1.0555...}\times 100\approx 105.55\%\approx 106\%$

Thus, males working in City C is approximately 106% of females working from City B.