Read the following table shows the total number of bikes sold by two (X and Y) different companies in four (K, L, M, and N) different cities and the total number of cars sold by these two companies in these cities. The table also shows the total number of bikes sold by company Y in these cities.

Cities	Bikes sold by (X and Y)	Cars sold by (X and Y)	Bikes sold by Y
K	328	450	210
L	560	980	320
M	440	730	90
N	620	350	195

Total number of cars sold by X in city N is 20% less than the total number of bikes sold by X in city M. Find the ratio of the total number of cars sold by Y in city N to the total number of bikes sold by Y in city K.

The correct answer is 1:3.

Let's break down the problem step-by-step using the data given in the table.

Step 1: Calculate the total number of bikes sold by company X in city M.

From the table:

• Total bikes sold by (X and Y) in city M = 440

• Total bikes sold by Y in city M = 90

Therefore, the number of bikes sold by X in city M is given by:

$\text{Bikes sold by X in city M}=440-90=350$

Step 2: Calculate the total number of cars sold by company X in city N.

The problem states that the total number of cars sold by X in city N is 20% less than the total number of bikes sold by X in city M.

$\text{Cars sold by X in city N}=350\times (1-0.20)=350\times 0.80=280$

Step 3: Calculate the total number of cars sold by company Y in city N.

From the table:

• Total cars sold by (X and Y) in city N = 350

Therefore, the number of cars sold by Y in city N is:

$\text{Cars sold by Y in city N}=350-280=70$

Step 4: Find the total number of bikes sold by company Y in city K.

From the table directly:

• Total bikes sold by Y in city K = 210

Step 5: Calculate the required ratio.

We need to find the ratio of total cars sold by Y in city N to total bikes sold by Y in city K:

$\text{Ratio}=\frac{70}{210}=\frac{1}{3}$

Thus, the required ratio is 1:3.