Read the following table shows the total number of bikes sold by two (X and Y) different companies in four (K, L, M, and N) different cities and the total number of cars sold by these two companies in these cities. The table also shows the total number of bikes sold by company Y in these cities.
| Cities | Bikes sold by (X and Y) | Cars sold by (X and Y) | Bikes sold by Y |
|---|---|---|---|
| K | 328 | 450 | 210 |
| L | 560 | 980 | 320 |
| M | 440 | 730 | 90 |
| N | 620 | 350 | 195 |
If total number of cars sold by Y in city K are two-fifth of the total number of bikes sold by Y in city K, then find the difference between the total number of cars sold by X in city K and bikes sold by X in city M.
Correct Answer :
16
Solution :
The correct option is 16.
Step-by-step Explanation:
1. Understand the data given in the table:
• City K: Total bikes sold by (X and Y) = 328
• City K: Total cars sold by (X and Y) = 450
• City K: Bikes sold by Y = 210
• City M: Total bikes sold by (X and Y) = 440
• City M: Bikes sold by Y = 90
2. Find the total number of bikes sold by X in city M:
Bikes sold by X in city M = Total bikes sold in city M - Bikes sold by Y in city M
3. Find the total number of cars sold by Y in city K:
According to the given condition, the total number of cars sold by Y in city K is two-fifth () of the total number of bikes sold by Y in city K.
4. Find the total number of cars sold by X in city K:
Cars sold by X in city K = Total cars sold in city K - Cars sold by Y in city K
5. Find the required difference:
Difference = Total number of cars sold by X in city K - Total number of bikes sold by X in city M
Thus, the required difference is 16.
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