The table shows the total number of bikes sold by two (X and Y) different companies in four (K, L, M, and N) different cities and the total number of cars sold by these two companies in these cities. The table also shows the total number of bikes sold by company Y in these cities.

Cities	Bikes sold by (X and Y)	Cars sold by (X and Y)	Bikes sold by Y
K	328	450	210
L	560	980	320
M	440	730	90
N	620	350	195

The total number of bikes sold by X in city M is what percentage more or less than the total number of cars sold by X and Y together in city N?

The correct option is 0%.

Step 1: Extract data from the table for City M and City N.

From the table provided:

• For City M:
- Total bikes sold by X and Y together = 440
- Bikes sold by Y = 90

• For City N:
- Total cars sold by X and Y together = 350

Step 2: Calculate the number of bikes sold by company X in City M.

The total bikes sold by company X in city M is the difference between total bikes sold by both companies (X and Y) in city M and the bikes sold by company Y in city M:

$\text{Bikes sold by X in city M}=440-90=350$

Step 3: Compare the values and calculate the percentage difference.

We are asked to find what percentage more or less the total number of bikes sold by X in city M is compared to the total number of cars sold by X and Y together in city N.

• Bikes sold by X in city M = 350
• Total cars sold by X and Y together in city N = 350

Since both values are equal (350 = 350), the difference is zero:

$\text{Difference}=350-350=0$

$\text{Percentage difference}=\left(\frac{0}{350}\right)\times 100\%=0\%$

Thus, the required percentage is 0%.