The table shows the total number of bikes sold by two (X and Y) different companies in four (K, L, M, and N) different cities and the total number of cars sold by these two companies in these cities. The table also shows the total number of bikes sold by company Y in these cities.

Cities	Bikes sold by (X and Y)	Cars sold by (X and Y)	Bikes sold by Y
K	328	450	210
L	560	980	320
M	440	730	90
N	620	350	195

The ratio of the total number of cars sold by X to Y in city L is 3:4 respectively. Find the total number of cars sold by X in city L is how many more or less than the total number of bikes sold by Y in N.

The correct option is 225.

Let us solve the problem step-by-step using the data provided in the table.

Step 1: Find the total number of cars sold by X in city L.
From the table, the total number of cars sold by both companies (X and Y) in city L is 980.
The ratio of the total number of cars sold by X to Y in city L is given as 3:4.
Total ratio parts = 3 + 4 = 7 parts.
Number of cars sold by X in city L = $\frac{3}{7}\times 980$

$\text{Number of cars sold by X in city L}=3\times 140=420$

Step 2: Find the total number of bikes sold by Y in city N.
Directly from the table, under the column "Bikes sold by Y" for city N, the value is 195.

Step 3: Calculate the difference between the total number of cars sold by X in city L and the total number of bikes sold by Y in city N.
Difference = Cars sold by X in L - Bikes sold by Y in N

$\text{Difference}=420-195=225$

Therefore, the total number of cars sold by X in city L is 225 more than the total number of bikes sold by Y in city N.