The total number of mountains in A is what percentage more or less than the average number of beaches in B and C?

Read the following bar graph and table carefully and answer the questions given below. The bar graph shows total number of beaches in five different countries. The table shows percentage of mountains out of total beaches and mountains together in these countries.

Countries	Percentage of mountains out of total beaches and mountains together
A	60%
B	75%
C	20%
D	80%
E	50%

The correct answer is 50%.

Step-by-step Explanation:

Step 1: Extract data from the bar graph for the number of beaches:

From the given bar graph, the number of beaches in each country is as follows:

• Number of beaches in Country A = 100
• Number of beaches in Country B = 80
• Number of beaches in Country C = 120

Step 2: Find the total number of mountains in Country A:

From the table, the percentage of mountains out of the total (beaches and mountains together) in Country A is 60%.

Therefore, the percentage of beaches in Country A out of the total is:

$\text{Percentage of beaches in A}=100\%-60\%=40\%$

Since the total number of beaches in Country A is 100, we can calculate the total number of beaches and mountains together in Country A:

$\text{Total (Beaches + Mountains) in A}=\frac{100}{40\%}=\frac{100}{0.4}=250$

Now, calculate the total number of mountains in Country A:

$\text{Mountains in A}=\text{Total}-\text{Beaches}=250-100=150$

Step 3: Calculate the average number of beaches in Country B and Country C:

The total number of beaches in Country B is 80 and in Country C is 120.

$\text{Average number of beaches in B and C}=\frac{80+120}{2}=\frac{200}{2}=100$

Step 4: Calculate the required percentage:

We need to find how much percentage the total number of mountains in A (150) is more than the average number of beaches in B and C (100):

$\text{Difference}=150-100=50$

$\text{Required Percentage}=\frac{50}{100}\times 100\%=50\%$

Thus, the total number of mountains in A is 50% more than the average number of beaches in B and C.