The wave length of Red light in the visible region is about 760 nm the energy of photon in that case will be:

The correct option is 1.64 eV.

Step-by-Step Explanation:

The energy of a photon is related to its wavelength by Planck's equation:

$E=\frac{hc}{\lambda }$

Where:
- $E$ is the energy of the photon,
- $h$ is Planck's constant ($h\approx 6.626\times {10}^{-34}\text{J s}$),
- $c$ is the speed of light ($c\approx 3\times {10}^8\text{m/s}$),
- $\lambda$ is the wavelength of the light ($\lambda =760\text{nm}=760\times {10}^{-9}\text{m}$).

Substitute the given values into the equation to calculate the energy in Joules:

$E=\frac{(6.626\times {10}^{-34}\text{J s})\times (3\times {10}^8\text{m/s})}{760\times {10}^{-9}\text{m}}$

$E\approx \frac{1.9878\times {10}^{-25}}{7.6\times {10}^{-7}}\text{J}$

$E\approx 2.616\times {10}^{-19}\text{J}$

To convert the energy from Joules (J) to electron-volts (eV), divide by the elementary charge value ($1\text{eV}=1.602\times {10}^{-19}\text{J}$):

$E=\frac{2.616\times {10}^{-19}\text{J}}{1.602\times {10}^{-19}\text{J/eV}}$

$E\approx 1.633\text{eV}$

Rounding to two decimal places gives approximately 1.64 eV.