The Whole Circle Bearing (WCB) of line AB is 150◦. The length of AB is 100 m. The latitude and departure values, respectively, for this line are:

To find the latitude and departure of line AB, we use the standard surveying definitions for these coordinates.

The latitude ($L$) of a line is its projection on the North-South meridian. It is calculated as:
$L=lcos\left(\theta \right)$
where:
- $l$ is the length of the line.
- $\theta$ is the Whole Circle Bearing (WCB) of the line.

The departure ($D$) of a line is its projection on the East-West parallel. It is calculated as:
$D=lsin\left(\theta \right)$

Given data:
- Length of the line ($l$) = 100 m
- Whole Circle Bearing ($\theta$) = 150°

Now, let's compute the latitude:
$L=100cos(150°)$

Since $cos(150°)=-cos(30°)=-0.866025$, we have:
$L=100\times (-0.866025)=-86.60\text{m}$

Next, let's compute the departure:
$D=100sin(150°)$

Since $sin(150°)=sin(30°)=0.5000$, we have:
$D=100\times 0.5000=+50.00\text{m}$

Therefore, the latitude is -86.60 and the departure is +50.00.