Question Details

Three persons A, B and C are standing in a queue not necessarily in the same order. There are 4 persons between A and B, and 7 persons between B and C. If there are 11 persons ahead of C and 13 behind A, what could be the minimum number of persons in the queue?

Options

A

22

B

28

C

32

D

38

Show Answer

Correct Answer :

Option A

22

Solution :

The correct option is 22.

To find the minimum number of persons in the queue, we need to arrange the positions of A, B, and C such that they overlap as much as possible, satisfying all the given conditions.

Let us define the positions of the individuals in the queue from front to back, where position 1 is the front-most position.
We are given the following conditions:
1. There are 4 persons between A and B.
2. There are 7 persons between B and C.
3. There are 11 persons ahead of C (meaning C is at position 12).
4. There are 13 persons behind A.

Since we want to minimize the total number of persons, C (who has 11 persons ahead of him) should be placed as far back in the relative order of A, B, and C as possible, while keeping A and B closer to the front. Let us try the arrangement where A is ahead of B, and B is ahead of C. That is, the order from front to back is A, then B, then C.

Let C be at position 12 (since there are 11 persons ahead of C).
If B is ahead of C with 7 persons between them, the position of B is calculated as:
Position of B = Position of C - 7 - 1 = 12 - 8 = 4.
Since Position of B = 4, there are 3 persons ahead of B, which is consistent with C having 11 persons ahead of him.

Now, there are 4 persons between A and B. Since we want to minimize the queue size and A has 13 persons behind him, let us place A ahead of B:
Position of A = Position of B - 4 - 1 = 4 - 5 = -1.
Since a position cannot be negative, A must be behind B. Let's place A behind B:
Position of A = Position of B + 4 + 1 = 4 + 5 = 9.

Let us check if this arrangement works:
- Position of B = 4.
- Position of A = 9.
- Position of C = 12.

Let us verify the conditions for this setup:
1. Persons between A and B: B is at 4, A is at 9. The positions between them are 5, 6, 7, and 8 (4 persons). This condition is satisfied.
2. Persons between B and C: B is at 4, C is at 12. The positions between them are 5, 6, 7, 8, 9, 10, and 11 (7 persons, which includes A at position 9). This condition is satisfied.
3. Persons ahead of C: C is at 12, so there are 11 persons ahead of C (positions 1 to 11). This condition is satisfied.
4. Persons behind A: A is at position 9. We are given that there are 13 persons behind A.

Thus, the total number of persons in the queue is:
Total = Position of A + Number of persons behind A
Total = 9 + 13 = 22.

Since all conditions are satisfied, the minimum number of persons in the queue is 22.

Unlock Our Free Library

Access expert-curated educational resources and study materials—completely free.

Discover more resources

You may also like

Mock Tests

View All
  • CTET
  • intermediate
  • No time limit
  • child development and pedagogy, mathematics, social science

  • SSC
  • intermediate
  • 2 hours and 30 mins
  • child development and pedagogy, mathematics, social science

Ask AI Tutor
5 left
Q1 View Question & Options
AI Tutor is solving this question...
Reading question context & options...