Question Details

Two couriers leave delivery hubs R and S, which are 211 km apart, travelling toward one another. The courier from R travels at 48 km/h and begins 30 minutes before the courier from S, who travels at 52 km/h. After how many hours from the departure of the courier at R will they meet?

Options

A

2.37 h

B

2.48 h

C

2.18 h

D

2.62 h

Show Answer

Correct Answer :

Option A

2.37 h

Solution :

The correct answer is 2.37 h.

Step 1: Calculate the distance covered by the courier from R before the courier from S departs.
The courier from hub R starts 30 minutes (which is 0.5 hours) earlier than the courier from hub S, traveling at a speed of 48 km/h.
Distance traveled by courier R initially=Speed×Time
Distance traveled by courier R initially=48 km/h×0.5 h=24 km
Thus, courier R covers 24 km before courier S begins moving.

Step 2: Calculate the remaining distance between the two couriers.
Subtract the 24 km already covered by courier R from the total initial distance of 211 km:
Remaining distance=211 km24 km=187 km
When courier S starts, the distance separating the two couriers is 187 km.

Step 3: Determine the relative speed of the two couriers.
Since the two couriers are traveling toward each other, their speeds add together to give their combined relative speed:
Relative speed=48 km/h+52 km/h=100 km/h

Step 4: Find the time taken for them to meet after courier S departs.
Divide the remaining distance by their relative speed:
Time after S departs=Remaining distanceRelative speed
Time after S departs=187 km100 km/h=1.87 hours

Step 5: Calculate the total time elapsed from the departure of the courier at R.
Add the initial 0.5 hours that courier R traveled alone to the 1.87 hours both couriers traveled together:
Total time=0.5 hours+1.87 hours=2.37 hours
They will meet 2.37 hours after the courier at hub R departs.

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