Two couriers leave delivery hubs R and S, which are 211 km apart, travelling toward one another. The courier from R travels at 48 km/h and begins 30 minutes before the courier from S, who travels at 52 km/h. After how many hours from the departure of the courier at R will they meet?
Correct Answer :
2.37 h
Solution :
The correct answer is 2.37 h.
Step 1: Calculate the distance covered by the courier from R before the courier from S departs.
The courier from hub R starts 30 minutes (which is 0.5 hours) earlier than the courier from hub S, traveling at a speed of 48 km/h.
Thus, courier R covers 24 km before courier S begins moving.
Step 2: Calculate the remaining distance between the two couriers.
Subtract the 24 km already covered by courier R from the total initial distance of 211 km:
When courier S starts, the distance separating the two couriers is 187 km.
Step 3: Determine the relative speed of the two couriers.
Since the two couriers are traveling toward each other, their speeds add together to give their combined relative speed:
Step 4: Find the time taken for them to meet after courier S departs.
Divide the remaining distance by their relative speed:
Step 5: Calculate the total time elapsed from the departure of the courier at R.
Add the initial 0.5 hours that courier R traveled alone to the 1.87 hours both couriers traveled together:
They will meet 2.37 hours after the courier at hub R departs.
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