Question Details

Two pumps, A and B, are capable of filling a liquid reservoir in 25 minutes and 30 minutes respectively. A third pump, C, can fill the reservoir at a rate of 15 litres per minute. If all three pumps function simultaneously to fill the reservoir in 10 minutes, determine the total capacity of the reservoir (in litres).

Options

A

612.5 litres

B

584.5 litres

C

500.5 litres

D

540.25 litres

E

562.5 litres

Show Answer

Correct Answer :

Option E

562.5 litres

Solution :

The correct answer is 562.5 litres.

Let us break down the problem step-by-step to find the total capacity of the reservoir.

Let the total capacity of the reservoir be V litres.

First, let us calculate the rate at which each pump fills the reservoir per minute:

1. Work rate of Pump A:
Pump A can fill the entire reservoir of capacity V in 25 minutes.
Rate of Pump A = V25 litres per minute.

2. Work rate of Pump B:
Pump B can fill the entire reservoir of capacity V in 30 minutes.
Rate of Pump B = V30 litres per minute.

3. Work rate of Pump C:
Pump C fills the reservoir at a given rate of 15 litres per minute.

When all three pumps function simultaneously, their combined filling rate per minute is the sum of their individual rates:
Combined Rate = Rate of A + Rate of B + Rate of C

Combined Rate=V25+V30+15

We are given that all three pumps working together fill the entire reservoir in 10 minutes.
Therefore, the total volume filled in 10 minutes is equal to V:

10×V25+V30+15=V

Now, let us solve this equation for V:

Divide both sides of the equation by 10:

V25+V30+15=V10

Rearrange the terms to group all terms containing V on one side:

15=V10-V25-V30

To combine the fractions on the right side, find the least common multiple (LCM) of the denominators 10, 25, and 30, which is 150:

15=15V-6V-5V150

Simplify the numerator:

15=4V150

15=2V75

Now, solve for V:

2V=15×75

2V=1125

V=11252=562.5

Thus, the total capacity of the reservoir is 562.5 litres.

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