Two rectangular gardens are there in a society such that the smaller garden is surrounded with the larger garden. Each garden has four gates. Gates of the smaller garden are open towards outside and the gates of the larger garden are open towards inside. All the gates are in the middle of the sides of the garden. Gates of the smaller garden face the gates of the larger garden.
Note: Only gates of different garden are facing each other.

Gate U of smaller park is second to the right of T. The gate which faces T is immediate right of N. The number of gates between U and T is one less than the number of gates between P and M. M is not adjacent to N. O faces the gate which is immediate right of R. R doesn’t face N. Gate O is not at the longer side of the garden. One of the gates is S.

Which among the following gate faces N?

The correct answer is S.

Step 1: Understand the Layout and Setup
There are two rectangular gardens, one smaller and one larger.
- The smaller garden is inside the larger garden.
- Each garden has 4 gates located at the middle of its 4 sides.
- Gates of the smaller garden open outward and face the gates of the larger garden (which open inward).
- Therefore, there are 4 gates on the inner (smaller) garden and 4 gates on the outer (larger) garden, making a total of 8 gates.
- Each side of a rectangular garden consists of 2 longer sides (opposite to each other) and 2 shorter sides (opposite to each other).

Step 2: Analyze the Clues for Inner and Outer Gates
Let's denote the inner (smaller garden) gates and outer (larger garden) gates.
From the prompt:
1. Gate U of the smaller park is second to the right of T.
Since U and T are in the smaller park (which has 4 gates total around a rectangle), being "second to the right" (or left) means U and T are directly opposite each other on the smaller garden!
Thus, U and T are inner gates, facing opposite sides.
The remaining two inner gates must be the other pair of opposite gates.

2. "The gate which faces T is immediate right of N."
Since T is an inner gate, the gate facing T must be an outer gate. Let's call the gate facing T as Outer Gate 1.
So, Outer Gate 1 is facing T, and it is immediate right of N (an outer gate). Thus, N is an outer gate.

3. "O faces the gate which is immediate right of R. R doesn’t face N. Gate O is not at the longer side of the garden."
Since O faces a gate (which is immediate right of R), O and R are on different gardens.
Gate O is not at the longer side of the garden, which means Gate O is located on one of the shorter sides.

4. "The number of gates between U and T is one less than the number of gates between P and M. M is not adjacent to N."
Between U and T (on the inner 4-gate ring), the number of gates between them along either side is 1.
So, number of gates between P and M must be 1 + 1 = 2.
In a 4-gate ring, having 2 gates between two gates along the circle (or opposite positions) means P and M are opposite each other!
Since U and T occupy one opposite pair of the inner garden, the other opposite pair of the inner garden must be occupied by the remaining inner gates, OR P and M are opposite each other on the outer garden.
Let's check the remaining letters: U, T, N, P, M, O, R, S (8 gates in total).
Inner gates: U, T, and two others.
Outer gates: N, and three others.

5. Let's determine which gates are Inner and Outer:
Inner gates: U, T, R, O (or P, M)
Since O faces the gate immediate right of R, O and R cannot be on the same ring if they face outer/inner directly, but R is adjacent to the gate faced by O.
Specifically, if R is an inner gate, its immediate right is an inner gate, which faces an outer gate O.
Thus, O is an outer gate, located on a shorter side of the outer garden.
Since O is an outer gate, the remaining outer gates are N, O, P, M (since P and M are opposite each other in a 4-gate outer ring).
Therefore:
- Outer gates (larger garden): N, O, P, M
- Inner gates (smaller garden): U, T, R, S

Step 3: Map the Outer and Inner Positions
Outer garden gates (clockwise order): N, P/M, O, M/P.
Since P and M are opposite each other:
- If N is at Position 1 (Outer), then opposite N is O (Position 3, shorter side).
- Positions 2 and 4 (Outer) are P and M.
- Gate facing T is immediate right of N. Going clockwise, immediate right of N is Position 2 (let's say P or M). So the gate facing T is at Position 2.
- R doesn't face N. N is at Position 1, so the gate facing N (Inner Position 1) cannot be R.
- Since Inner gates are U, T, R, S:
- U and T are opposite each other (Positions 2 and 4).
- R and S are opposite each other (Positions 1 and 3).
- Since R doesn't face N (Position 1), the gate facing N must be S!

Conclusion:
The gate that faces N is S.