Four of the following five are alike in a certain way and thus form a group. Find the one who doesn’t belong to the group?

Study the following information carefully and answer the questions given below:

Six persons – A, B, C, D, E and F sit in a row and all are facing north but not in same order as given. Each of them has different number of bags. None of them has bags less than 15 and more than 60. Only two persons sit between E and the one who has 35 bags, and neither of them sits at the extreme ends. The number of persons sitting to the right of E is one less than the number of persons sitting to the left of A. The one who has two bags less than C sits second to the left of A who sits adjacent to C. F sits to the immediate right of D who has even square number of bags. A has 18 bags less than B who has 20 bags more than D. E has prime number of bags and 15 bags more than the one who sits two places away from B.

How many bags does F have more or fewer than the person seated at the rightmost position in the row?

The correct answer is 15.

Step 1: Determine the seating arrangement from left to right (Positions 1 to 6).

Six persons (A, B, C, D, E, and F) sit in a row facing north.

Neither E nor the person with 35 bags sits at the extreme ends (Position 1 or Position 6), and exactly two persons sit between them. Therefore, E and the person with 35 bags must occupy Position 2 and Position 5.

The number of persons sitting to the right of E is one less than the number of persons sitting to the left of A.

If E sits at Position 2, there are 4 persons to the right of E. Thus, there must be $4+1=5$ persons to the left of A, placing A at Position 6 (extreme right).

Since E is at Position 2, the person with 35 bags sits at Position 5.

A sits adjacent to C, which places C at Position 5 (having 35 bags).

The person sitting second to the left of A (Position 4) has 2 bags less than C.

$35-2=33$

So, the person at Position 4 has 33 bags.

Step 2: Determine the positions of D, F, and B.

F sits to the immediate right of D, meaning D and F occupy adjacent seats [D, F].

The only available adjacent vacant seats are Position 3 and Position 4. Therefore, D sits at Position 3 and F sits at Position 4 (with 33 bags).

The remaining person, B, sits at Position 1.

Step 3: Calculate the number of bags for each person.

D has an even square number of bags between 15 and 60. The available options are 16 and 36.

B has 20 bags more than D:

$B=D+20$

A has 18 bags less than B:

$A=B-18=D+2$

E sits two places away from B (Position 3, which is occupied by D) and has 15 bags more than D:

$E=D+15$

E has a prime number of bags:

If $D=16$, then $E=16+15=31$ (which is prime).

If $D=36$, then $E=36+15=51$ (not prime).

Thus, $D=16$, $E=31$, $B=36$, and $A=18$.

Step 4: Final seating arrangement and bag counts:

Position 1: B (36 bags)

Position 2: E (31 bags)

Position 3: D (16 bags)

Position 4: F (33 bags)

Position 5: C (35 bags)

Position 6: A (18 bags)

Step 5: Calculate the final difference.

F has 33 bags, and the person at the rightmost position (A) has 18 bags.

Difference = $33-18=15$

Therefore, F has 15 more bags than the person seated at the rightmost position in the row.