What is the position of C with respect to the one who has maximum number of bags?

Study the following information carefully and answer the questions given below:

Six persons – A, B, C, D, E and F sit in a row and all are facing north but not in same order as given. Each of them has different number of bags. None of them has bags less than 15 and more than 60. Only two persons sit between E and the one who has 35 bags, and neither of them sits at the extreme ends. The number of persons sitting to the right of E is one less than the number of persons sitting to the left of A. The one who has two bags less than C sits second to the left of A who sits adjacent to C. F sits to the immediate right of D who has even square number of bags. A has 18 bags less than B who has 20 bags more than D. E has prime number of bags and 15 bags more than the one who sits two places away from B.

The correct option is Fourth to the right.

Step-by-step Explanation:

Step 1: Determine the seating arrangement

There are six persons: A, B, C, D, E, and F sitting in a row facing North (positions 1 to 6 from left to right).

1. "Only two persons sit between E and the one who has 35 bags, and neither of them sits at the extreme ends."

Since neither E nor the one with 35 bags sits at extreme ends (positions 1 and 6), they must sit at positions 2 and 5.

Case 1: E is at position 2, and the person with 35 bags is at position 5.

Case 2: E is at position 5, and the person with 35 bags is at position 2.

2. "The number of persons sitting to the right of E is one less than the number of persons sitting to the left of A."

If E is at position 2: Number of persons to the right of E = 4. Thus, number of persons to the left of A must be 4 + 1 = 5. So, A is at position 6 (extreme right).

If E is at position 5: Number of persons to the right of E = 1. Thus, number of persons to the left of A must be 1 + 1 = 2. So, A is at position 3.

3. "The one who has two bags less than C sits second to the left of A who sits adjacent to C."

In Case 1 (E = position 2, A = position 6):

A is adjacent to C. Since A is at position 6, C must be at position 5 (so C has 35 bags).

The person sitting second to the left of A (position 4) has 2 bags less than C. So position 4 has 35 - 2 = 33 bags.

In Case 2 (E = position 5, A = position 3):

The person second to the left of A is at position 1. C must be adjacent to A (position 2 or 4). But position 2 has 35 bags. If C is at position 2, C has 35 bags, and position 1 has 33 bags.

4. "F sits to the immediate right of D who has even square number of bags."

This requires D and F to sit together in the order [D, F].

In Case 1:

Positions filled: E (2), (D/F at 3,4 or 1,2 - but 2 is E). Since positions 3 and 4 are empty, D is at position 3 and F is at position 4.

Then the remaining position for B is position 1.

So the seating order from left to right (positions 1 to 6) is: B, E, D, F, C, A.

Step 2: Determine the number of bags for each person

From the clues:

1. C has 35 bags (Position 5).

2. The person 2nd to the left of A (F, Position 4) has 2 bags less than C: $F=35-2=33$ bags.

3. D has an even square number of bags. The allowed range is 15 to 60. Even squares in this range are 16 and 36.

4. "B has 20 bags more than D": $B=D+20$.

If D = 16, then B = 36.

If D = 36, then B = 56.

5. "A has 18 bags less than B": $A=B-18$.

If B = 36, then A = 18.

If B = 56, then A = 38.

6. "E has prime number of bags and 15 bags more than the one who sits two places away from B."

B is at position 1. The person two places away from B is D (position 3).

So $E=D+15$.

If D = 16, then E = 16 + 15 = 31 (which is a prime number).

If D = 36, then E = 36 + 15 = 51 (which is not a prime number).

Therefore, D = 16.

Thus, the number of bags are:

D = 16

E = 31

B = 16 + 20 = 36

A = 36 - 18 = 18

F = 33

C = 35

Comparing all bag numbers: B has the maximum number of bags (36 bags).

B sits at position 1 (extreme left).

C sits at position 5.

The position of C with respect to B is 4 places to the right, which is Fourth to the right.