What is the sum of the floor numbers of Q and the one who likes pink colour live?Study the following information carefully and answer the questions given below:
Six persons –P, Q, R, S, T and U are living on different floors of the six-storey building such that the lowermost floor is numbered as one and the floor immediately above it is numbered as two and so on. Each of them likes different colours- Red, Blue, Grey, Black, Pink and White but not necessarily in the same order. Only two floors are between the one who likes grey colour and U who lives on an odd numbered floor. P lives immediately above U. The number of floors below P is one more than the number of floors above the one who likes white. Only one floor is between Q and the one who likes pink colour. The one who likes Pink colour and the one who likes blue colour live on the adjacent floor. Neither U nor P likes blue colour. The number of floors between the one who likes black and S is two less than the number of floors between S and the one who like red. T likes neither grey nor red.
Correct Answer :
8
Solution :
To find the sum of the floor numbers of Q and the person who likes pink, we can determine the step-by-step arrangement of the six floors (numbered 1 to 6 from bottom to top) and the colours liked by each person:
Step 1: Determine the positions of U, P, and the Grey and White colours
1. U lives on an odd-numbered floor (1, 3, or 5).
2. Only two floors are between U and the one who likes Grey.
3. P lives immediately above U.
4. The number of floors below P is one more than the number of floors above the one who likes White (i.e., Number of floors below P = Number of floors above White + 1).
Let's analyze the possibilities for U's floor:
• If U lives on Floor 5: P must live on Floor 6. The number of floors below P is 5, meaning the number of floors above White must be 4, so White is on Floor 2. Since U is on Floor 5, the person who likes Grey must be on Floor 2 (with two floors, 3 and 4, in between). This is a contradiction because Floor 2 cannot have both White and Grey. Thus, U cannot be on Floor 5.
• If U lives on Floor 1: P must live on Floor 2. The number of floors below P is 1, so the number of floors above White must be 0, placing White on Floor 6. Grey is on Floor 4 (with two floors, 2 and 3, in between). If we test this scenario, we find it contradicts the constraints regarding the spacing between Black, Red, and S.
• If U lives on Floor 3: P must live on Floor 4. The number of floors below P is 3, which means the number of floors above White is 2, placing White on Floor 4 (so P likes White). Grey is on Floor 6 (with two floors, 4 and 5, in between). This is a valid configuration.
Step 2: Place Q, Blue, and Pink
1. Only one floor is between Q and the one who likes Pink.
2. Pink and Blue are on adjacent floors.
3. Neither U nor P likes Blue. Since P (Floor 4) likes White, and U (Floor 3) cannot like Blue, Blue must be on Floor 2.
4. This means Pink must be on Floor 3 (U likes Pink) because Pink is adjacent to Blue (Floor 2).
5. Since Q is separated from Pink (Floor 3) by exactly one floor, Q must live on Floor 5.
Step 3: Place S, T, R and the remaining colours (Red, Black)
1. The number of floors between the one who likes Black and S is two less than the number of floors between S and the one who likes Red.
2. Let's place S on Floor 2 (who likes Blue). If S is on Floor 2, Black is on Floor 1, and Red is on Floor 5 (liked by Q). The number of floors between Black (Floor 1) and S (Floor 2) is 0. The number of floors between S (Floor 2) and Red (Floor 5) is 2. Since 0 is indeed two less than 2, this satisfies the condition.
3. T likes neither Grey nor Red. Since Floor 6 likes Grey and Floor 5 (Q) likes Red, T must live on Floor 1 (who likes Black).
4. The remaining person R must live on Floor 6 (who likes Grey).
The final arrangement is:
• Floor 6: R (Grey)
• Floor 5: Q (Red)
• Floor 4: P (White)
• Floor 3: U (Pink)
• Floor 2: S (Blue)
• Floor 1: T (Black)
Conclusion:
The floor number of Q is 5.
The floor number of the person who likes pink (U) is 3.
The sum of their floor numbers is:
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