What will come in the place of ‘?’ in the following equation, if ‘+’ and ‘–’ are interchanged and also ‘×’ and ‘÷’ are interchanged?
53 – 48 × 6 ÷ 9 + 11 = ?

To find the value that comes in place of the question mark (?), we need to modify the given equation according to the specified rule and then solve it using the standard rules of arithmetic (BODMAS/PEMDAS).

The given equation is:
53 – 48 × 6 ÷ 9 + 11 = ?

According to the problem statement, we must perform the following interchanges:
1. Interchange '+' and '–' (which means '+' becomes '–' and '–' becomes '+')
2. Interchange '×' and '÷' (which means '×' becomes '÷' and '÷' becomes '×')

Applying these changes to the equation:
- The '–' after 53 becomes '+'
- The '×' after 48 becomes '÷'
- The '÷' after 6 becomes '×'
- The '+' after 9 becomes '–'

The modified equation is:
53 + 48 ÷ 6 × 9 – 11 = ?

Now, we solve the equation following the order of operations (division and multiplication first from left to right, then addition and subtraction from left to right):

Step 1: Perform Division
First, evaluate the division part: 48 ÷ 6
$48÷6=8$
Substitute this back into the equation:
53 + 8 × 9 – 11 = ?

Step 2: Perform Multiplication
Next, evaluate the multiplication part: 8 × 9
$8\times 9=72$
Substitute this back into the equation:
53 + 72 – 11 = ?

Step 3: Perform Addition and Subtraction
Now, perform addition: 53 + 72
$53+72=125$
Finally, perform subtraction: 125 – 11
$125-11=114$

Thus, the value that replaces the '?' is 114.