Question Details

X and Y run a 3 km race along a circular course of length 300 m. Their speeds are in the ratio of 3 : 2. If they start together in the same direction, how many times would the first one pass the other (the start off is not counted passing)?

Options

A

2

B

3

C

4

D

5

Show Answer

Correct Answer :

Option B

3

Solution :

The correct option is 3.

Let's break down the solution step-by-step to understand why the first runner passes the second runner exactly 3 times during the race.

Step 1: Understand the race parameters
The total length of the race is 3 km, which is equal to 3000 m.
The race is run along a circular course of length 300 m.
The speeds of the two runners, X and Y, are in the ratio of 3 : 2. Since X has a higher speed, X is the first runner who will overtake or pass Y.
Let the speed of X be 3v and the speed of Y be 2v, where v is a constant factor of speed.

Step 2: Determine when the first passing (meeting) occurs
X and Y start together from the same point in the same direction.
For X to pass Y for the first time after the start, X must gain a lead of exactly one full round (circle length) over Y.
The circumference of the circular track is 300 m. Therefore, X passes Y when X has run 300 m more than Y.
Let us find the relative speed of X with respect to Y. Since they are running in the same direction, their relative speed is:
Relative Speed = 3 v - 2 v = v
The time taken for X to gain a lead of 300 m (the first passing) is:
t = 300 v

Step 3: Calculate the distance covered by X at the first passing
During this time t, the distance covered by X is:
D X = Speed of X × t = 3 v × 300 v = 900 m
This means X passes Y for the first time when X has run exactly 900 m.

Step 4: Find the total number of passings during the entire race
Since the race is a continuous run along the same track, X will pass Y every time X covers an additional 900 m.
X passes Y at distances of:
1st passing: 900 m
2nd passing: 900 + 900 = 1800 m
3rd passing: 1800 + 900 = 2700 m
4th passing (if it occurred): 2700 + 900 = 3600 m
Since the total race distance is 3000 m, X finishes the race at 3000 m. The 4th passing would require X to reach 3600 m, which is beyond the finish line of the race.
Therefore, X passes Y at 900 m, 1800 m, and 2700 m. X passes Y exactly 3 times during the 3 km race.

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