Question Details

X can complete one-third of a certain work in 6 days, Y can complete one-third of the same work in 8 days and Z can complete three-fourth of the same work in 12 days. All of them work together for n days and then X and Z quit and Y alone finishes the remaining work in 823 days. What is n equal to?

Options

A

3

B

4

C

5

D

6

Show Answer

Correct Answer :

Option B

4

Solution :

The correct answer is Option 2: 4.


Step 1: Calculate the total time required by each person to complete the whole work individually.

For X:
X completes 1/3 of the work in 6 days.
Therefore, X takes 6 × 3 = 18 days to complete the full work.

For Y:
Y completes 1/3 of the work in 8 days.
Therefore, Y takes 8 × 3 = 24 days to complete the full work.

For Z:
Z completes 3/4 of the work in 12 days.
Therefore, Z takes 12 × (4/3) = 16 days to complete the full work.


Step 2: Determine their 1-day work rate.

X's 1-day work = 118


Y's 1-day work = 124


Z's 1-day work = 116


Step 3: Calculate the combined 1-day work of X, Y, and Z.

Combined 1-day work of (X + Y + Z) = 118+124+116


Find the LCM of denominators 18, 24, and 16, which is 144.

118+124+116=8+6+9144=23144


So, together they do 23144 unit of work per day.


Step 4: Calculate the work completed by Y alone in the remaining days.

Y works alone for 823=263 days.


Work done by Y alone in 263 days = 263×124=1336


Step 5: Calculate the remaining work done together by X, Y, and Z.

Remaining work (work done in the initial n days by X, Y, and Z together) = 1-1336=2336


Step 6: Find the value of n.

Since X, Y, and Z work together for n days, the work done in n days is equal to n × (Combined 1-day work).

n×23144=2336


n=2336×14423=14436=4


Therefore, the value of n is equal to 4.

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