Question Details

20 men and 35 women can complete a piece of work in ‘y’ and ‘y – 3’ days respective while 15 men and 20 women can complete same piece of work in ‘x – 4’ and ‘x’ days respectively. If each man are 60% more efficient than each woman, then find difference between x and y.

Options

A

11

B

21

C

14

D

12

E

15

Show Answer

Correct Answer :

Option A

11

Solution :

The correct answer is Option 11.


Step 1: Understand the ratio of efficiency between a man and a woman.

Let the efficiency of a woman be w units per day.

Since each man is 60% more efficient than each woman, the efficiency of a man (m) is:

m=w+0.60w=1.6w=85w

Therefore, the ratio of efficiencies of a man to a woman is:

mw=85

Let m=8 units/day and w=5 units/day.


Step 2: Formulate equations for total work using the given data.

Case 1: 20 men can complete the work in y days, while 35 women can complete the same work in y-3 days.

Total Work = Work done by 20 men in y days = 20×m×y

Total Work = Work done by 35 women in y-3 days = 35×w×(y-3)

Equating the total work expressions:

20×8×y=35×5×(y-3)

160y=175(y-3)

160y=175y-525

15y=525

y=35


Step 3: Calculate the value of x.

Case 2: 15 men can complete the work in x-4 days, while 20 women can complete the same work in x days.

Total Work = Work done by 15 men in x-4 days = 15×m×(x-4)

Total Work = Work done by 20 women in x days = 20×w×x

Equating these two total work expressions:

15×8×(x-4)=20×5×x

120(x-4)=100x

120x-480=100x

20x=480

x=24


Step 4: Find the difference between y and x.

Difference = y-x=35-24=11


Thus, the difference between x and y is 11.

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