${31}^2-\sqrt{169}=62\%\text{of}?+{24}^2$

What should come in place of question mark (?) in the following questions?

To find the value that comes in place of the question mark (?), let us set up the equation from the given problem:

${31}^2-\sqrt{169}=62\%\text{of}x+{24}^2$

Where $x$ represents the unknown value (?).

Step 1: Simplify the terms on both sides of the equation.

Calculate the squares and the square root:
• ${31}^2=961$
• $\sqrt{169}=13$
• ${24}^2=576$

Substitute these calculated values back into the equation:

$961-13=62\%\text{of}x+576$

Step 2: Simplify the left side.

$948=62\%\text{of}x+576$

Step 3: Isolate the percentage term by subtracting 576 from both sides.

$948-576=62\%\text{of}x$

$372=62\%\text{of}x$

Step 4: Solve for $x$.

Express 62% as a fraction:
$372=\frac{62}{100}\times x$

Multiply both sides by 100 and divide by 62:

$x=\frac{372\times 100}{62}$

Since $372÷62=6$:

$x=6\times 100=600$

Therefore, the value that should come in place of the question mark is 600.