37, 50, 65, 82, 101, 122, 143
Find the wrong number in the following number series.

The correct option is 143.

To find the wrong number in the given series, let us analyze the pattern followed by the numbers in the sequence:

37, 50, 65, 82, 101, 122, 143

Let us express each term in relation to consecutive squares:

$6^2+1=36+1=37$

$7^2+1=49+1=50$

$8^2+1=64+1=65$

$9^2+1=81+1=82$

${10}^2+1=100+1=101$

${11}^2+1=121+1=122$

${12}^2+1=144+1=145$

Alternatively, we can look at the differences between consecutive terms:
50 - 37 = 13
65 - 50 = 15
82 - 65 = 17
101 - 82 = 19
122 - 101 = 21
The differences are consecutive odd numbers starting from 13.
Following this pattern, the next difference should be 23:
122 + 23 = 145

Therefore, the last number should be 145 instead of 143. Hence, 143 is the wrong number in the series.