5/9 of a number is equal to twenty five percent of a second number. Second number is equal to 1/4 of a third number. The value of the third number is 2960. How much is the 30% of the first number?

The correct answer is 99.9.

Let us denote the first, second, and third numbers as _N1, _N2, and _N3 respectively.

We are given the value of the third number:
$$N_3=2960$$

Next, we are told that the second number is equal to 1/4 of the third number:
$$N_2=\frac{1}{4}\times N_3$$
Substituting the value of _N3:
$$N_2=\frac{1}{4}\times 2960=740$$

The problem states that 5/9 of the first number is equal to 25% of the second number. We can express 25% as 1/4:
$$\frac{5}{9}\times N_1=25\%\times N_2$$
$$\frac{5}{9}\times N_1=\frac{1}{4}\times 740$$
$$\frac{5}{9}\times N_1=185$$
Solving for _N1:
$$N_1=185\times \frac{9}{5}$$
$$N_1=37\times 9=333$$

Finally, we need to find 30% of the first number _N1:
$$30\%\times N_1=0.3\times 333$$
$$0.3\times 333=99.9$$
Thus, the 30% of the first number is 99.9.