Question Details

A 50 kg block is connected to another hanging mass M by an inextensible massless string through two massless pulley as shown in figure. Neglect pulley friction, the minimum value of M required to start upward motion of block is ______ kg. (Rounded off to one decimal place)


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Correct Answer :

19

Solution :

The correct answer is 19.

1. Understanding the Pulley System and Tension:
Based on the diagram, the inclined plane is at an angle of 30° with the horizontal. The 50 kg block is connected to a movable pulley. A string is anchored near the top fixed pulley, wraps around this movable pulley, passes over the fixed pulley, and hangs vertically to support the mass M.

Let T be the tension in the inextensible string. For the hanging mass M at the verge of upward motion, the tension in the string is balanced by its weight:
T = M g
Because the string wraps around the movable pulley attached to the 50 kg block, two segments of the string pull the block up the incline. Thus, the total pulling force Fpull acting on the block up the incline is:
F pull = 2 T = 2 M g

2. Forces Acting on the 50 kg Block:
For the block to start moving up the inclined plane, the pulling force must overcome both the component of gravity acting down the incline and the maximum static friction force (fs,max).

The component of gravity acting down the incline is:
F g,|| = m g sin ( 30 ° ) = 50 × g × 0.5 = 25 g
The maximum static friction force opposing the upward motion is:
f s,max = μ s N = μ s m g cos ( 30 ° )
Taking the coefficient of static friction for the rough incline as μs0.3:
f s,max 0.3 × 50 × g × 3 2 13 g

3. Calculating the Minimum Mass M:
Setting up the force balance at the threshold of motion:
F pull = F g,|| + f s,max
Substituting the derived expressions:
2 M g = 25 g + 13 g
Dividing both sides by g:
2 M = 38
M = 19  kg
Thus, the minimum value of M required to start upward motion of the block is 19 kg.

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  • GATE
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  • mechanical engineering

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