Question Details

A boy boarded a train on 4th June, 2020 at Nagarcoil for Madgaon. The train departed at 22:30 hours from Nagarcoil and reached Madgaon at 04:30 hours on 6th June, 2020. If the distance covered by the train during this time interval is 1145 km, the average speed of the train was nearly

Options

A

36.5 km/h

B

38.5 km/h

C

40.5 km/h

D

42.5 km/h

Show Answer

Correct Answer :

Option B

38.5 km/h

Solution :

The correct option is 38.5 km/h.

To find the average speed of the train, we need to calculate the total distance traveled and the total time taken for the journey.

Step 1: Determine the total distance covered
Given distance = 1145 km

Step 2: Calculate the total time taken
- On 4th June 2020: The train departed at 22:30 hours.
Time traveled on 4th June = 24:00 - 22:30 = 1 hour 30 minutes (1.5 hours)

- On 5th June 2020: The train traveled for the entire day.
Time traveled on 5th June = 24 hours

- On 6th June 2020: The train reached Madgaon at 04:30 hours.
Time traveled on 6th June = 4 hours 30 minutes (4.5 hours)

Total time taken = 1.5 hours + 24 hours + 4.5 hours = 30 hours

Step 3: Calculate the average speed
The formula for average speed is:

Average Speed=Total DistanceTotal Time

Substituting the given values into the formula:

Average Speed=1145 km30 hours38.16 km/h

Rounding off to the nearest available option, the average speed of the train was nearly 38.5 km/h.

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