A motorbike leaves point A at 1 pm and moves towards point B at a uniform speed. A car leaves point B at 2 pm and moves towards point A at a uniform speed which is double that of the motorbike. They meet at 3:40 pm at a point which is 168 km away from
Correct Answer :
378
Solution :
Correct Option: B
The motorbike that left A travelled 168 km from 1:00 p.m. to 3:40 p.m., i.e. in 2 2/3 hours or 8/3 hours.
The car that left B, started at 2:00 p.m. and travelled till 3:40 p.m., i.e. for 1 2/3 hours or 5/3 hours.
The car would've travelled 5/8th of the distance as the bike, but since the car travelled at twice the speed, the car would've
travelled 10/8th of the distance, i.e. (10/8) x 168 = 210 km.
Therefore, total distance between A and B = 168 + 210 = 378 km.
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