A particular station of All India Radio, New Delhi, broadcasts on a frequency of 1,368 kHz (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is : [speed of light, c=3.0×10⁸ ms⁻¹]

The correct answer is 219.3 m.

Step 1: Understand the Given Data
We are given the following values:
Frequency of the radio wave ($f$ or $\nu$) = 1,368 kHz
Speed of light ($c$) = $3.0\times {10}^8{\text{ms}}^{-1}$

Step 2: Convert Units to SI System
Frequency must be converted from kilohertz (kHz) to hertz (Hz):

$f=\mathrm{1,368}\text{kHz}=\mathrm{1,368}\times {10}^3\text{Hz}=1.368\times {10}^6{\text{s}}^{-1}$

Step 3: Formula for Wavelength
The relation between the speed of light ($c$), frequency ($f$), and wavelength ($\lambda$) is given by the wave equation:

$c=f\times \lambda$

$\lambda =\frac{c}{f}$

Step 4: Substitute the Values
Plugging the values into the formula:

$\lambda =\frac{3.0\times {10}^8{\text{ms}}^{-1}}{1.368\times {10}^6{\text{s}}^{-1}}$

$\lambda =\frac{3.0}{1.368}\times {10}^{8-6}\text{m}$

$\lambda =2.19298\times {10}^2\text{m}$

$\lambda \approx 219.3\text{m}$

Thus, the wavelength of the electromagnetic radiation emitted by the transmitter is 219.3 m.