Question Details

A person covers 132 km distance in ‘t’ hours by travelling some distance by car and some by train and speed of train is 20% more than Speed of car. If ratio of distance travelled by car and train is 4 : 7 and car covers 48 km distance with 24 km/h speed in (t+0.5) hours ,then find speed of train(approximately) ?

Options

A

100km/h

B

94 km/h

C

80 km/h

D

110 km/h

Show Answer

Correct Answer :

Option B

94 km/h

Solution :

The correct option is 94 km/h.

Let us solve the problem step-by-step.

Step 1: Understand the given information
- Total distance = 132 km
- Total time taken = t hours
- Ratio of distance covered by car to train = 4 : 7
- Speed of train is 20% more than the speed of car.
- Car covers 48 km distance with speed of 24 km/h in (t + 0.5) hours.

Step 2: Find the value of t
Using the formula:

Time = Distance Speed


For the car's secondary condition:
Time taken = (t + 0.5) hours
Distance = 48 km
Speed = 24 km/h

t + 0.5 = 48 24 = 2

t = 2 - 0.5 = 1.5  hours

Step 3: Calculate the distance travelled by car and train in the main journey
Total distance = 132 km, divided in the ratio 4 : 7.
Sum of ratio parts = 4 + 7 = 11 parts.

Distance travelled by car:

D car = 4 11 × 132 = 48  km

Distance travelled by train:

D train = 7 11 × 132 = 84  km

Step 4: Relate the speeds of car and train
Let the speed of the car be Scar = S km/h.
Since the speed of the train is 20% more than the speed of the car:

S train = S + 0.20 S = 1.2 S

Step 5: Set up the total time equation
Total time for covering 132 km is t = 1.5 hours.

Time car + Time train = 1.5


Substitute distance and speed values:

48 S + 84 1.2 S = 1.5

Simplify the second fraction:

84 1.2 = 70


So the equation becomes:

48 S + 70 S = 1.5

118 S = 1.5

S = 118 1.5 = 236 3  km/h

Step 6: Find the speed of the train

S train = 1.2 × S = 6 5 × 236 3

S train = 2 × 236 5 = 472 5 = 94.4  km/h

Rounding off to the nearest whole number gives approximately 94 km/h.

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