A room having the dimensions as mentioned in the chart below has a table, a bed and a chair. There are three books kept on the table (side by side) and also a lamp having radius, 3.5 inch. Now, on the basis of information given below answer the following?

Sr. No.	Object	Length	Breadth	Height
1.	Room	18 feet	12 feet	12 feet
2.	Bed	3.5 feet	6 feet	3 feet
3.	Table	3 feet	4 feet	4 feet
4.	Chair	2 feet	2.5 feet	4 feet
5.	Books	12 inch	6 inch	3 inch

What is the area of the table which is uncovered by any of the objects?

The correct option is 1473.52 sq. inch.

Step 1: Understand the dimensions of the table and convert them to inches.
From the table provided in the question:
Length of the table = 3 feet
Breadth of the table = 4 feet

Since 1 foot = 12 inches:
Length of the table in inches = $3\times 12=36\text{ inches}$
Breadth of the table in inches = $4\times 12=48\text{ inches}$

Total area of the top of the table:
$\text{Total Area}=\text{Length}\times \text{Breadth}$

$\text{Total Area}=36\times 48=1728\text{ sq. inch}$

Step 2: Calculate the area covered by the 3 books.
From the table, the dimensions of one book's surface (base area) placed on the table are:
Length = 12 inches
Breadth = 6 inches

Area of one book:
$\text{Area of 1 book}=12\times 6=72\text{ sq. inch}$

Area covered by 3 books:
$\text{Area of 3 books}=3\times 72=216\text{ sq. inch}$

Step 3: Calculate the area covered by the circular lamp base.
The radius of the lamp base ($r$) = 3.5 inches.

Area covered by the circular lamp:
$\text{Area of lamp}=\pi r^2$

$\text{Area of lamp}=\frac{22}{7}\times {\left(3.5\right)}^2=\frac{22}{7}\times 12.25=38.48\text{ sq. inch}$ (or accurately $38.48451\text{ sq. inch}$ using standard $\pi \approx 3.14159$ gives $3.14159\times 12.25\approx 38.48\text{ sq. inch}$).

Step 4: Calculate total covered area and uncovered area of the table.
Total area covered on the table by books and lamp:
$\text{Total Covered Area}=216+38.48=254.48\text{ sq. inch}$

Uncovered area of the table:
$\text{Uncovered Area}=\text{Total Area of Table}-\text{Total Covered Area}$

$\text{Uncovered Area}=1728-254.48=1473.52\text{ sq. inch}$

Hence, the area of the table which is uncovered by any of the objects is 1473.52 sq. inch.