Question Details

A large tank holds a blend of mango juice and lime water in the ratio of 9 : x respectively. When 500 ml of this blend is drawn out from the tank and poured into a separate container already holding 100 ml of lime water, the ratio of mango juice to lime water in the new container becomes 3 : 7. Find the value of x.

Options

A

16

B

15

C

14

D

20

E

17

Show Answer

Correct Answer :

Option A

16

Solution :

Correct Answer: The correct answer is 16.

Step-by-Step Explanation:

Step 1: Determine the composition of the drawn blend
The tank holds a blend of mango juice and lime water in the ratio of 9:x.
When 500 ml of this blend is drawn out, the ratio of mango juice to lime water in the drawn 500 ml portion remains 9:x.

The total number of ratio parts is:
9+x

The quantity of mango juice present in the 500 ml drawn blend is:
Mango Juice=500×99+x=45009+x ml

The quantity of lime water present in the 500 ml drawn blend is:
Lime Water in blend=500×x9+x=500x9+x ml

Step 2: Calculate the total quantities in the new container
The 500 ml blend is poured into a separate container that already holds 100 ml of lime water.
Therefore, the new container contains:

Total Mango Juice:
Mango Juice=45009+x ml

Total Lime Water:
Lime Water=500x9+x+100 ml

Simplifying the expression for total lime water:
Total Lime Water=500x+100(9+x)9+x=500x+900+100x9+x=600x+9009+x ml

Step 3: Set up the ratio equation
The ratio of mango juice to lime water in the new container becomes 3:7.

Writing the ratio as an equation:
Mango JuiceLime Water=37

Substituting the respective expressions:
45009+x600x+9009+x=37

Canceling the common denominator 9+x from both the numerator and denominator:
4500600x+900=37

Step 4: Solve for x
Simplify the left fraction by dividing both numerator and denominator by 300:
152x+3=37

Cross-multiply to solve for x:
15×7=3×(2x+3)

105=6x+9

Subtract 9 from both sides:
6x=96

Divide by 6:
x=16

Thus, the value of x is 16.

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