Anil mixes cocoa with sugar in the ratio 3:2 to prepare mixture A, and coffee with sugar in the ratio 7:3 to prepare mixture B. He combines mixtures A and B in the ratio 2:3 to make a new mixture C. If he mixes C with an equal amount of milk to make a drink, then the percentage of sugar in this drink will be

The correct answer is 17.

Let us solve the problem step-by-step to find the percentage of sugar in the final drink.

Step 1: Understand the composition of Mixture A
Mixture A consists of cocoa and sugar in the ratio 3:2.
This means that in any quantity of Mixture A, the fraction of sugar is:
$\frac{2}{3+2}=\frac{2}{5}$

Step 2: Understand the composition of Mixture B
Mixture B consists of coffee and sugar in the ratio 7:3.
This means that in any quantity of Mixture B, the fraction of sugar is:
$\frac{3}{7+3}=\frac{3}{10}$

Step 3: Calculate the fraction of sugar in Mixture C
Anil combines Mixture A and Mixture B in the ratio 2:3 to make Mixture C.
Let us assume he takes 2 units of Mixture A and 3 units of Mixture B, making a total of 5 units of Mixture C.
The total amount of sugar in these 5 units of Mixture C is:
$\text{Sugar in C}=2\times \left(\frac{2}{5}\right)+3\times \left(\frac{3}{10}\right)$
Let us compute the sum:
$\text{Sugar in C}=\frac{4}{5}+\frac{9}{10}=\frac{8}{10}+\frac{9}{10}=\frac{17}{10}=1.7\text{units}$
So, in 5 units of Mixture C, there are 1.7 units of sugar.
The fraction of sugar in Mixture C is:
$\frac{1.7}{5}=0.34$

Step 4: Calculate the percentage of sugar in the final drink
Anil mixes Mixture C with an equal amount of milk to make the final drink.
Let us say he mixes 5 units of Mixture C with 5 units of milk.
The total volume of the drink becomes:
$5+5=10\text{units}$
Since milk contains no sugar, the total amount of sugar in the final drink remains 1.7 units.
Thus, the fraction of sugar in the drink is:
$\frac{1.7}{10}=0.17$
Converting this fraction to a percentage:
$0.17\times 100\%=17\%$

Therefore, the percentage of sugar in the drink is 17%.