Carefully analyze the given details and answer the question that follows.

There are three branches (Branch A, Branch B, and Branch C) in enterprise K. The ratio of male to female employees in Branch A is 7:10. The number of female employees in Branch C is 20% more than the number of female employees in Branch A. The number of male employees in Branch C is six more than that of female employees in Branch C. The average number of male employees across all three branches is 39 and the number of male employees in Branch B is 35. The number of female employees in Branch B is 25% more than the number of female employees in Branch C.

The number of female employees in Branch B is what percent more or less than the number of female employees in Branch A?

The correct answer is 50%.

Step 1: Define variables based on the given ratios and relationships.

Let the common ratio multiplier for male and female employees in Branch A be $x$.

Given ratio of male to female employees in Branch A = 7 : 10

$\text{Male employees in Branch A }\left(M_A\right)=7x$

$\text{Female employees in Branch A }\left(F_A\right)=10x$

The number of female employees in Branch C ($F_C$) is 20% more than in Branch A:

$F_C=10x+(0.20\times 10x)=12x$

The number of male employees in Branch C ($M_C$) is six more than female employees in Branch C:

$M_C=12x+6$

Step 2: Calculate the value of $x$.

Average number of male employees across all three branches = 39

Total male employees in all three branches = 39 × 3 = 117

Given, male employees in Branch B ($M_B$) = 35

$M_A+M_B+M_C=117$

$7x+35+(12x+6)=117$

$19x+41=117$

$19x=76$

$x=4$

Step 3: Calculate the number of female employees in each branch.

Female employees in Branch A ($F_A$):

$F_A=10\times 4=40$

Female employees in Branch C ($F_C$):

$F_C=12\times 4=48$

Female employees in Branch B ($F_B$) are 25% more than in Branch C:

$F_B=48+(0.25\times 48)=48+12=60$

Step 4: Find the percentage by which female employees in Branch B are more than Branch A.

Difference = 60 - 40 = 20

$\text{Percentage More}=\left(\frac{60-40}{40}\right)\times 100=\left(\frac{20}{40}\right)\times 100=50\%$

Therefore, the number of female employees in Branch B is 50% more than the number of female employees in Branch A.