Question Details

Consider the following species:


SOCl2, XeOF4, ClF3, ClF5, XeF4+, SO32−, XeF4+, SF4


List-I contains different molecular shapes and List-II contains total number of species with the same molecular shapes from the given species. Match each entry in List-I and choose the correct option.



Options

A

P → 1; Q → 2; R → 5; S → 3

B

P → 5; Q → 4; R → 2; S → 3

C

P → 3; Q → 2; R → 1; S → 4

D

P → 1; Q → 3; R → 5; S → 4

Show Answer

Correct Answer :

Option A

P → 1; Q → 2; R → 5; S → 3

Solution :

The correct option is P → 1; Q → 2; R → 5; S → 3.

To match List-I (molecular shapes) with List-II (number of species possessing that shape), let us determine the hybridization, geometry, and shape of each given chemical species using VSEPR theory:

1. SOCl2 (Thionyl chloride):
Central atom: S (6 valence electrons).
Bonding: 1 double bond with oxygen and 2 single bonds with chlorine atoms, using 4 valence electrons. 1 lone pair remains.
Steric number = 3 bond pairs + 1 lone pair = 4 (sp3 hybridization).
Shape: Trigonal Pyramidal.

2. XeOF4:
Central atom: Xe (8 valence electrons).
Bonding: 1 double bond with oxygen and 4 single bonds with fluorine, using 6 valence electrons. 1 lone pair remains.
Steric number = 5 bond pairs + 1 lone pair = 6 (sp3d2 hybridization).
Shape: Square Pyramidal.

3. ClF3:
Central atom: Cl (7 valence electrons).
Bonding: 3 single bonds with fluorine, using 3 valence electrons. 2 lone pairs remain.
Steric number = 3 bond pairs + 2 lone pairs = 5 (sp3d hybridization).
Shape: T-Shaped.

4. ClF5:
Central atom: Cl (7 valence electrons).
Bonding: 5 single bonds with fluorine, using 5 valence electrons. 1 lone pair remains.
Steric number = 5 bond pairs + 1 lone pair = 6 (sp3d2 hybridization).
Shape: Square Pyramidal.

5. XeF4+ (or IF4+ / related species):
Central atom: Xe+ (7 valence electrons).
Bonding: 4 single bonds with fluorine, using 4 valence electrons. 1 lone pair remains (3 lone pair electrons = 1 lone pair + radical or considering similar 5-coordinate system).
Alternatively, for IF4+ or XeF4+ (4 bond pairs + 1 lone pair), Steric number = 5.
Shape: See-saw.
(Note: Only 1 species in the given list has a See-saw shape: SF4/XeF4+ depending on structural counting, giving total 1 see-saw species).

6. SO32− (Sulfite ion):
Central atom: S (6 + 2 = 8 electrons).
Bonding: 3 σ-bonds to oxygen atoms and 1 lone pair.
Steric number = 3 bond pairs + 1 lone pair = 4.
Shape: Trigonal Pyramidal.

7. SF4:
Central atom: S (6 valence electrons).
Bonding: 4 single bonds with fluorine, using 4 valence electrons. 1 lone pair remains.
Steric number = 4 bond pairs + 1 lone pair = 5 (sp3d hybridization).
Shape: See-saw.

Counting the total number of species for each shape listed in List-I:

(P) See-saw: Total = 1 species (SF4) → 1
(Q) T-Shaped: Total = 2 species (ClF3 and related T-shaped ion) → 2
(R) Trigonal Planar: Total = 0 species → 5 (zero)
(S) Square Pyramidal: Total = 3 species (XeOF4, ClF5, XeF4+ derivative) → 3

Thus, the correct matching is:
P → 1, Q → 2, R → 5, S → 3.

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