Direction (36-40): Read the information carefully and answer the following questions

The table given below shows the number of accounts opened by four different branches (A, B, C and D) in four different months.

Months/Branches	A	B	C	D
January	15	20	22	25
February	18	25	12	24
March	30	40	42	45
April	35	32	40	16

In branch X, Total number of accounts opened in month of March is 25% more than the number of accounts opened by D in month of April. Find the sum of the accounts opened by X in month March and number of accounts opened by C in the month of February.

The correct answer is 32.

Let us break down the solution step-by-step:

Step 1: Find the number of accounts opened by branch D in April
From the given table, look at the row for "April" and the column for branch "D". The number of accounts opened is 16.

Step 2: Calculate the number of accounts opened by branch X in March
The problem states that the number of accounts opened by branch X in March is 25% more than those opened by D in April.

$\mathrm{Accounts} \mathrm{by} X \mathrm{in} \mathrm{March}=16+(25\% \mathrm{of} 16)$

$=16+(\frac{25}{100}\times 16)$

$=16+4=20$

Step 3: Find the number of accounts opened by branch C in February
From the table, look at the row for "February" and the column for branch "C". The number of accounts opened is 12.

Step 4: Calculate the required sum
We need to find the sum of the accounts opened by X in March and by C in February.

$\mathrm{Sum}=20+12=32$