Question Details

Direction (36-40): Read the information carefully and answer the following questions

The table given below shows the number of accounts opened by four different branches (A, B, C and D) in four different months.

Months/BranchesABCD
January15202225
February18251224
March30404245
April35324016

In branch X, Total number of accounts opened in month of March is 25% more than the number of accounts opened by D in month of April. Find the sum of the accounts opened by X in month March and number of accounts opened by C in the month of February.

Options

A

35

B

30

C

28

D

32

Show Answer

Correct Answer :

Option D

32

32

Solution :

To find the required sum, let us break down the calculations step-by-step based on the data given in the table.

Step 1: Find the number of accounts opened by branch D in the month of April.
From the table, we locate the row for April and the column for branch D.
The number of accounts opened by D in April = 16.

Step 2: Calculate the number of accounts opened by branch X in the month of March.
We are given that the number of accounts opened in branch X in March is 25% more than the number of accounts opened by D in April.
Number of accounts opened by X in March = (Accounts by D in April) + 25% of (Accounts by D in April)
Number of accounts opened by X in March = 16 + (0.25 * 16)
Number of accounts opened by X in March = 16 + 4 = 20.

Step 3: Find the number of accounts opened by branch C in the month of February.
From the table, we locate the row for February and the column for branch C.
The number of accounts opened by C in February = 12.

Step 4: Calculate the required sum.
Sum = (Accounts by X in March) + (Accounts by C in February)
Sum = 20 + 12 = 32.

Thus, the sum of the accounts opened by X in March and by C in February is 32.

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