Direction (41–52): What will come in the place of (?) mark in following question?

${?}^3\times 6+\sqrt[3]{512}=170$

The correct answer is 3.

Given equation:
${?}^3\times 6+\sqrt[3]{512}=170$
Let the unknown value in the place of the question mark (?) be represented by $x$. Therefore, the equation becomes:
$x^3\times 6+\sqrt[3]{512}=170$

First, we find the cube root of 512:
$\sqrt[3]{512}=8$
(since $8^3=8\times 8\times 8=512$)

Substituting this value back into the equation, we get:
$x^3\times 6+8=170$

Subtract 8 from both sides of the equation:
$x^3\times 6=170-8$
$x^3\times 6=162$

Divide both sides by 6:
$x^3=\frac{162}{6}$
$x^3=27$

Taking the cube root on both sides:
$x=\sqrt[3]{27}$
$x=3$
(since $3^3=3\times 3\times 3=27$)

Thus, the value that will come in the place of the question mark (?) is 3.